Answer:
1,140,000,000
Step-by-step explanation:
Answer: 1 -2ax²+2x-ax
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a rectangle: length x width
Replacing with the values given:
A = (2x+1) (1-ax)
A = [2x(1)] + [2x(-ax)] +[ 1(1)]+ [1 (-ax)]
A = 2x- 2ax² +1- ax
A = 1 -2ax²+2x-ax
In conclusion, the correct option is 1 -2ax²+2x-ax
Feel free to ask for more if needed or if you did not understand something.
The slope and y-intercept of this function is
B. The slope is 5/6, The y-intercept is (0, -3
<h3>How to find the slope and the y-intercept</h3>
Linear function is a function of the form y = mx + c
m = slope
c = intercept
The slope is represented as m, The slope by definition is the ratio change of the output values to the input values
the slope, m calculated using the points (0, -3) and (6, 2)
m = (y₀ - y₁) / (x₀ - x₁)
m = (2 - -3) / (6 - 0)
m = (5) / (6)
m = 5/6
c = y intercept, from the table
c = -3
Learn more about slope of linear functions at:
brainly.com/question/29323505
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Answer:
B
Step-by-step explanation:
Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:

Compute the probability that a person does not have the disease as follows:

The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:


Thus, the probability of the test indicating that the person does not have the disease is 0.1452.