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Lelu [443]
2 years ago
11

A substance has a specific heat capacity of 2.0 J/g °C. How many joules are needed to raise the temperature of 30.0 g of this su

bstance from 0°C to15°C?
a. 1 J

b. -1 J

c. -900 J

d. 900 J
Chemistry
2 answers:
Vesnalui [34]2 years ago
7 0

Answer:

\Large \boxed{\sf 900 \  J}

Explanation:

Use formula

\displaystyle \sf Energy\ (J)=mass \ (g) \times specific \ heat \ capacity \ (Jg^{-1}\°C^{-1}) \times change \ in \ temperature \ (\°C)

Substitute the values in formula and evaluate

\displaystyle \sf Energy\ (J)=30.0\ g \times 2.0 \ Jg^{-1}\°C^{-1} \times (15\°C-0\°C)

\displaystyle Q=30.0 \times 2.0 \times (15-0  )=900

3241004551 [841]2 years ago
5 0

Answer:

g

Explanation:

know what you think about th can get it

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ANTONII [103]

Answer:

Percent error = 25%

Explanation:

Given data:

Measured density of water = 1.25 g/mL

Accepted density value of water = 1 g/mL

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Formula:

Percent error = (measured value - accepted value / accepted value) × 100

Now we will put the values in formula:

Percent error = (1.25 g/mL - 1 g/mL /1 g/mL )× 100

Percent error = (0.25 g/mL /1 g/mL )× 100

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What does Na2S formula mean?; What is the two in Na2S called?; How do you write Na2S?; What state of matter is Na2S?
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The chemical compound sodium sulfide has the formula Na2S. It is written as Na_{2}S. It has a crystalline state. Na is followed by a two or 2. this indicates that the molecule has two of the specified element's atoms.

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In all, this molecule consists of one sulfur atom and two sodium atoms.

A compound's chemical formula, which uses symbols for combining atoms, reveals the composition of the complex. We require the valency of the combining parts in order to write the formula.

The sodium sulfide chemical formula must be written down. So sodium and sulfur make up the two elements in the chemical. Sodium has a valency of +1, while sulfur has a +2.

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1 year ago
2N2H4+ N2O4———3N2+4H2O SalmaKhan99 avatar How many grams of N2 gas will be formed by reacting 100g of N2H4 and 200g of N2 Kindly
Alona [7]

Answer:

131.26 g

Explanation:

From the balanced equation,

2 moles of N₂H₄reacts with 1 mole of N₂O₄ to give 3 moles of N₂

Now number of moles of N₂H₄ present in 100 g N₂H₄ is n = 100 g/molar mass N₂H₄.

Molar mass N₂H₄ = 2 × 14.01 g/mol + 1 × 4 g/mol = 28.02 g/mol + 4 g/mol = 32.02 g/mol

n₁ = 100/32.02 = 3.123 mol

Also

Now number of moles of N₂O₄ present in 200 g N₂O₄ is n = 200 g/molar mass N₂O₄.

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n₂ = 200/92.02 = 2.173 mol

Since the mole ratio of N₂H₄  to N₂O₄ is 2 : 1, We require 2 × 2.173 mol N₂H₄  to react with 2.173 mole N₂O₄  

Number of moles of N₂H₄ required is 4.346. But the number of moles of N₂H₄  present is 3.123 so N₂H₄  is the limiting reagent.

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From n = m/M where n = number of moles of nitrogen gas = 4.6845 mol and M = molar mass of nitrogen gas = 28.02 g/mol and m = mass of nitogen gas.

m = nM = 4.6845 mol × 28.02 g/mol = 131.26 g

So the mas of nitrogen gas produced is 131.26 g

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