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icang [17]
4 years ago
6

How many half-lives would something have gone through if you had 75% daughter product and 25% parent?

Chemistry
1 answer:
levacccp [35]4 years ago
6 0

Answer:

Two Half-lives

Explanation:

Let number of Parent nuclei Initially present be X,

Then, finally \frac{X}{4} Parent nuclei Will remain with \frac{3X}{4} daughter nuclei.

In one half- life , parent nuclei becomes half of initial.

So, starting with X parent nuclei,

After one half-life, it will degrade to \frac{X}{2} .

After another half life , Parent nuclei will become half of \frac{X}{2}

Which is equal to \frac{X}{4}.

So, Parent nuclei have to go through Two half-lives.

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Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

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[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

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3 years ago
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2 years ago
Calculate the mass of oxygen in 30 g of CH NH COOH?​
Naya [18.7K]

Molar mass of CH2NH2COOH - 75

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