Answer:
2H₂O₂ → 2H₂O + O₂
Explanation:
H₂O₂ → H₂O + O₂
The above equation can be balance as illustrated below:
H₂O₂ → H₂O + O₂
There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:
2H₂O₂ → 2H₂O + O₂
Now, the equation is balanced.
**** check ****
Element >>> Left Side >>> Right Side
H >>>>>>>>> 4 >>>>>>>>> 4
O >>>>>>>>> 4 >>>>>>>>> 4
Answer:
C
Explanation:
If you walk near them, they will fly away
1. A
2. base
3. strong ones have more h30 weak ones have more OH
4. strong ones have more OH weak ones have more H30
5. <span>One of the main differences between acids and bases is that acids have a pH that is less than 7 and bases have a pH that is greater than 7. When dissolved in water, acids are substances that will cause the concentration of hydrogen ions (H+) to increase. Bases, when dissolved in water, will instead cause the number of hydroxide ions (OH-) to increase.6.Idk </span>
Answer:
B. 67.6/Hg(200.5)= .337. 10.8/S(32.1)= .336. 21.6/O(16)= 1.35--> .337/.336= 1 .336/.336= 1 1.35/.336= 4. Formula= HgSO4
Explanation:
Answer:
ΔSv = 0.1075 KJ/mol.K
Explanation:
Binary solution:
∴ a: solvent
∴ b: solute
in equilibrium:
- μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)
⇒ Ln (1 - Xb) = ΔG/RT
∴ ΔG = ΔHv - TΔSv
⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R
∴ Xb → 0:
⇒ Ln(1) = ΔHv/RT - ΔSv/R
∴ T = T*b....normal boiling point
⇒ 0 = ΔHv/RT*b - ΔSv/R
⇒ ΔSv = (R)(ΔHv/RT*b)
⇒ ΔSv = ΔHv/T*b
∴ T*b = 80°C ≅ 353 K
⇒ ΔSv = (38 KJ/mol)/(353 K)
⇒ ΔSv = 0.1075 KJ/mol.K