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Delvig [45]
3 years ago
6

Higher amplitudes sound will have a _____________________ sound while lower amplitude will have a __________________________ sou

nd. 10. The speed of sound is dependent on density and temperature of the medium being used so that higher density or temperature will yield a (higher / lower) speed (Kinetic Molecular Theory). 11. Give an example of any resonance heard: 12. Give an example of any echo heard. 13. Give an example of any evidence that sound is energy traveling in waves.
Physics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

9)  HIGHER  AND LOWER INTESITY, 10) speed of sound must decrease.

11) guitar the strings, flute,  12) In the mountains,  13) sound of a low frequency horn (sub-wofeer)

     

Explanation:

In this exercise we are asked to complete the sentences.

9) the intensity of the sound is the square of the amplitude, the missing words are

      HIGHER INTESITY

      LOWER INTENSITY

10) the speed of sound is

          v = \sqrt{\frac{B}{\rho} }

and it is also related to temperature

         v = v_o \sqrt{1+ \frac{T}{273} }

We must be careful since the compressibility modulus (B) changes significantly between the solid, liquid and gaseous states, if we are in the same medium, the speed of sound decreases with increasing density. For a higher density the speed of sound decreases

Also the speed of sound increases with temperature, but its effect is less,

Therefore, by having these two effects in the opposite direction, the change in density is more important, so the speed of sound must decrease.

.

11) when you listen to a guitar the strings resonate with the instrument body

   on the flute has a resonance between the blown air and the flute tube

12) When you are in front of a tall object, the sound is reflected and the echo is heard.

      In the mountains, in the squares where there is a large object that reflects in sound

13) when we hear the sound of a low frequency horn (sub-wofeer) we feel the vibration of the air, this is an effect of the pressure energy of the sound on our chest

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Answer:

A

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A is just the most logical. Sagittarius doesn't mean anything here.

Light does not originate anywhere. DNA is not formed in a black hole.

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In a compression wave, particles in the medium move
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An astronaut is a short distance away from her space station without a tether rope. She has a large wrench. What should she do w
Hitman42 [59]

Answer: b. Throw it directly away from the space station.

Explanation:

According to <u>Newton's third law of motion</u>, <em>when two bodies interact between them, appear equal forces and opposite senses in each of them.</em>  

To understand it better:  

Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude but in the opposite direction on the first.  

So, if the astronaut throws the wrench away from the space station (in the opposite direction of the space station), according to Newton's third law, she will be automatically moving towards the station and be safe.

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3 years ago
Find the frequency of a wave of wavelength 2.5m and speed 400 m/s
Sedaia [141]

Answer:

The frequency of wave is 160Hz.

Explanation:

Given that the formula of speed is V = f×λ where V represents speed, f is frequency and λ is wavelength.

So first thing, you have to make frequency the subject by dividing wavelength on both sides :

v = f \times λ \:

v \div  λ =  f \times λ \div λ

f =  \frac{v}{λ}

Next you have to substitute the value of v and f into the formula :

Let λ = 2.5m,

Let v = 400m/s,

f =  \frac{400}{2.5}

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7 0
3 years ago
A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

200=200ω²

ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
4 years ago
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