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3 years ago

8

Jan participates in a bowling tournament. Her average score for 11 games is 204. Without her lowest score, her average is 207. W

hat is Jan’s lowest score?

1 answer:

Gala2k [10]3 years ago

3 0

I hope this help but in case you cant see it the answer is 174

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What is the answer for the second one?<br> 7% is the same as ??

ipn [44]

Answer:

0.07

Step-by-step explanation:

Just put the value of the percent

40, 90, or 7 over 100

40/100, 90/100, 7/100

This yields

0.4, 0.9, 0.07

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3 years ago

Plz help due tomorrow

zaharov [31]

Answer:

A is the first step

Step-by-step explanation:

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3 years ago

If PQRS is a rhombus, find m

egoroff_w [7]

Answer:

m<PQR = 82°

Step-by-step explanation:

In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.

Therefore:

(4x - 27)° = (2x + 7)°

Solve for x

4x - 27 = 2x + 7

Collect like terms

4x - 2x = 27 + 7

2x = 34

Divide both sides by 2

2x/2 = 34/2

x = 17

✔️m<PQR = (4x - 27) + (2x + 7)

Plug in the value of x

m<PQR = (4*17 - 27) + (2*17 + 7)

m<PQR = 41 + 41

m<PQR = 82°

6 0

3 years ago

A baseball is thrown up in the air. The table shows the height y (in feet) of the baseball after x seconds. Write an equation fo

frutty [35]

im sorry im not here to anwser but i love your pfp and i love the anime

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3 years ago

A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. If the basin is completely filled with water, how muc

jarptica [38.1K]

Answer:

$39.3 ft^3$

Step-by-step explanation:

The cylindrical basin has a height of 2 ft and a diameter of 5 ft.

To find the amount of water that will completely fill up the basin, we simply need to find the volume of the basin.

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius of the basin (half the diameter) = 2.5 ft

h = height of the basin

Hence, the volume is:

$V = \pi * 2.5^2 * 2$

$V = 39.27 ft^3$ ≅ $39.3 ft^3$

The cylindrical basin can hold up to $39.3 ft^3$ of water.

5 0

3 years ago

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