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3 years ago

A dime is dropped from a building at a

Mathematics

1 answer:

Rasek [7]3 years ago

5 0

Answer:

8 seconds

Step-by-step explanation:

Given :

h(t) = -16t2 + initial height

Initial height = 1024 feets

By the time it hits the ground, h(t) = 0

Equation becomes :

0 = - 16t² + 1024

Solve for t

-16t² = 1024

t² = 1024 / -16

t² = 64

t = √64

t = 8

Hence, it will take 8 seconds

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

Solve the following for equation a. 8 = a/b

ruslelena [56]

Answer:

a=8b

Step-by-step explanation:

To do this we just need to isolate a

so we can multiply the equation by b

then we will get

a=8b

3 0

3 years ago

Can you help me please I don't understand.

Dimas [21]

B. A and b parrel never touch

C. 44

D.136

E.44

Hope this helps a little

8 0

3 years ago

A frozen dinner at the grocery store is purchased for $2.20 a wholesale and is a marked up for 40 percent. a customer wants to b

iren [92.7K]

First of all, you surely do have a lot of incorrect grammar in your statement. I can't understand a word that you are asking.

3 0

3 years ago

Find the value of the variable.

NemiM [27]

Answer:

x=y[base side of isosceles triangle]

x²+y²=19²

x=√{19²/2)}

x=13.44

y=13.44

7 0

2 years ago