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3 years ago

True or False: a mixture that has a uniform composition and uniform properties in all its parts is called a homogeneous mixture

Chemistry

1 answer:

sattari [20]3 years ago

6 0

Answer:

True

Explanation:

The composition and properties are so uniform that it's difficult to physically differentiate them.

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Which substance is the oxidizing agent in this reaction? fe2o3+3co→2fe+3co2 express your answer as a chemical formula?

erma4kov [3.2K]

Equation is as follow,

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

Oxidation:

3 CO → 3 CO₂

Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,

3 CO → 3 CO₂ + 6 e⁻

Reduction:

Fe₂O₃ → 2 Fe

Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,

Fe₂O₃ + 6e⁻ → 2 Fe

Result:
Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.

4 0

3 years ago

When 10.0 grams of sulfur reacts with fluorine gas at a pressure of 2.69 atmosphere in a 5.00 L container at 0.00 degrees Celsiu

Gwar [14]

Answer:

74.1%

Explanation:

Based on the reaction:

S₈ + 16F₂ → 8SF₄

1 mole of sulfur reacts with 16 moles of F₂ to produce 8 moles of SF₄

To solve this question we must find the moles of each reactant in order to find the moles of SF₄. Thus, we can find the theoretical mass produced. Percent yield is:

Percent yield = Actual yield (25.0g) / Theoretical yield * 100

Moles S₈: 256.52g/mol

10.0g * (1mol / 256.52g) = 0.0390 moles

Moles F₂:

PV = nRT

PV/RT = n

Where P is pressure in atm, V is volume in liters, R is gas constant and T is absolute temperature (0°C = 273.15K)

2.69atm*5.00L / 0.082atmL/molK*273.15K = n

0.600 moles = n

For a complete reaction of 0.600 moles F₂ are required:

0.600mol F₂ * (1mol S₈ / 8 mol F₂) = 0.075 moles S₈

As there are just 0.0390 moles, S₈ is limiting reactant.

The theoretical moles and mass of SF₄ -Molar mass: 108.07g/mol- is:

0.0390 moles S₈ * (8mol SF₄ / 1mol S₈) = 0.312 moles SF₄ * (108.07g) =

33.7g

Percent yield = 25.0g / 33.7g * 100

= 74.1%

6 0

3 years ago

The complete combustion of 0.611 g of a snack bar in a calorimeter (Ccal = 6.15 kJ/°C) raises the temperature of the calorimeter

Bogdan [553]

Focus your attention to the units of the given data and the unit of the final measurement you're going to solve. Through dimensional analysis,you know that the working equation would be:

Food Value = CcalΔT/m
Food value = (6.15 kJ/°C)(1.29 °C)/0.611 g = 12.98 kJ/g

Convert kJ to cal (1 kJ = 239 cal)
Food value = 12.98*239 = 3,103.28 cal/g

4 0

3 years ago

Exactly 1.5 g of a fuel burns under conditions of constant pressure and then again under conditions of constant volume. In measu

nata0808 [166]

Answer:

Process B : constant pressure condition

Process A : constant volume condition

Explanation:

In case of constant pressure, some of the energy is used to do work on the surrounding to keep pressure constant. Due to this, the total heat energy is less than in case of constant volume. In Case of constant Volume all of heat is available, produced in reaction because no work is done.

If we look at our data,we will find that process B has energy 23.3 KJ which is less than process A, the energy of which is 25.9 KJ. It means Process B is occurred at constant pressure condition and Process A has occurred at constant volume condition

8 0

4 years ago

Which of the following is the strongest reducing agent ? Cl , Ar , K , Ca+2

Rama09 [41]

I think the answer would be K.

6 0

4 years ago