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Answer:
22 g of CO2 are obtained from decomposition of 50 g of CaCO3
Explanation:
Answer:
The diluted solution is 0.65 M
Explanation:
Dilution formula to solve the problem is:
M concentrated . V concentrated = M Diluted . V diluted
We can also make a rule of three though.
In 1000 mL of concentrated solution, we have 13.1 moles of HNO₃
So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃
This moles are also in 0.500 L of diluted solution, the new molarity will be:
0.327 mol / 0.5L = 0.65 M
Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.
If we replace in the formula
13.1 M . 25 mL = 500 mL . M diluted
M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M
Answer: ATP Adenosine triphosphate
Explanation: During light reaction plants produce glucose and as well as ATP and NADPH as another products. Now during the Dark or light independent reaction there is no presence of light energy to fuel the process so ATP is used as an alternative to fix CO2 molecules.
2Cu(s) + O2(g) --> 2CuO(s)