What is Class Night in Puerto Rico?
1 answer:
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Answer:
The force that must be applied to maintain the vane speed constant is 2771.26 N
Explanation:
Given;
turning angle of the vane = 120°
control volume velocity, u = 10 m/s
absolute velocity, v = 30 m/s
nozzle area = 0.004 m²
The force acting on the vane has horizontal and vertical components:
Based on Reynolds general control volume system;
The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)
where;
ρ is the density of water = 1000 kg/m³
W is the relative velocity = Absolute velocity - control volume velocity
W = v - u
= 30 - 10 = 20m/s
∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N
The vertical force component of the system, ∑Fy = ρW²A(sinθ)
∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N
The magnitude of the force applied
The force that must be applied to maintain the vane speed constant is 2771.26 N
Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
