1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lilit [14]
3 years ago
10

EMB agar is a medium used in the identification and isolation of pathogenic bacteria. It contains digested meat proteins as a so

urce of organic nutrients. Two indicator dyes, eosin and methylene blue, inhibit the growth of gram-positive bacteria and distinguish between lactose fermenting and nonlactose fermenting organisms. Lactose fermenters form metallic green or deep purple colonies, whereas the nonlactose fermenters form completely colorless colonies. EMB agar is an example of which of the following?A selective medium, a differential medium, and a complex medium
Engineering
1 answer:
Ilya [14]3 years ago
5 0

Answer:

A selective medium, a differential medium, and a complex medium.

Explanation:

A selective media is a microbiological media which only support the growth of a particular specie or types of species of microorganisms,this media acts in such a way to inhibit or hinder the growth of other microorganisms.

Differential media are media that acts to Identifying particular strains of microorganisms of similar species.

Complex media are media used for the growth of microorganisms this which contains complex or a wide range of nutrients with chemical composition which may be difficult to determine.

You might be interested in
You must signal [blank] before any turn or lane change.
Soloha48 [4]
A. 5 seconds :) Good luck!
5 0
4 years ago
What the answer fast
anygoal [31]
Viscosity isT=u(U/y) where T is shear stress & u is velocity and y is thr length
The answer is =2.57
7 0
3 years ago
Everyone why are you reporting my answers i didnt do anything to you
masya89 [10]

Answer:

IDK

Explanation:

same thing is happening to me

5 0
3 years ago
Read 2 more answers
Consider a 400 mm × 400 mm window in an aircraft. For a temperature difference of 90°C from the inner to the outer surface of th
Sergeeva-Olga [200]

Answer:

HEAT LOST

polycarbonate = 252 W

soda lime glass = 1680 W

aerogel = 16.8 W

COST associated with heat loss

polycarbonate = $ 262.08

soda lime glass =  $ 1,747.2

aerogel =  $ 17.472

The cost associated with heat loss is maximum in Soda Lime and minimum in Aerogel

Explanation:

Given that;

surface area for each window = 0.4m * 0.4m = 0.16m^2

DeltaT = 90°C, L = 12mm = 0.012m

thermal conductivity of soda line can be gotten from tables in FUNDAMENTALS OF HEAT AND MASS TRANSFER

so at 300K

KsL = 1.4 W/mK

Kag = 0.014 W/mK

Kpc = 0.21 W/mK

Now HEAT LOSS

for polycarbonate;

Qpc  = -KA dt/dx

NOTE (  heat flows from high temperature region to low temperature regions. so the second temperature would be smaller compared to the initial causing a negative in the change in temperature)

so Qag  = (0.21 * 0.16 * 90) / 0.012

= 252 W

for soda lime glass;

Qsl  = (1.4 * 0.16 * 90) / 0.012

= 1680 W

for aerogel

Qaq  = (0.014 * 0.16 * 90) / 0.012

= 16.8 W

Now for COST associated with heat lost

for polycarbonate;

cost = Qpc * 130 * 8 * 1/1000

= 252 * 130 * 8 * 1/1000

= $ 262.08

for soda lime glass;

cost = 1680 * 130 * 8 * 1/1000

= $ 1,747.2

for aerogel

cost = 16.8 * 130 * 8 * 1/1000

= $ 17.472

Therefore the cost associated with heat loss is maximum in Soda Lime and minimum in Aerogel

6 0
3 years ago
Consider a half-wave rectifier circuit with a triangular-wave input of LaTeX: 6V6 V peak-to-peak amplitude and zero average valu
Varvara68 [4.7K]

The question is not complete. We are supposed to find the average value of v_o.

Answer:

v_o,avg = 0.441V

Explanation:

Let t1 and t2 be the start and stop times of the output waveforms. Thus, from the diagram i attached, using similar triangles, we have;

3/(T/4) = 0.7/t1

So, 12/T = 0.7/t1

So, t1 = 0.7T/12

t1 = 0.0583 T

Also, from symmetry of triangles,

t2 = T/2 - t1

So, t2 = T/2 - 0.0583 T

t2 = 0.4417T

Average of voltage output is;

v_o,avg = (1/T) x Area under small triangle

v_o,avg = (1/T) x (3 - 0.7) x (T/4 - t1)

v_o,avg = (1/T) x (2.3) x (T/4 - 0.0583 T)

v_o,avg = (1/T) x 2.3 x 0.1917T

T will cancel out to give;

v_o,avg = 0.441V

8 0
3 years ago
Other questions:
  • (a) Draw the Moore finite state machine (FSM) of an electronic combination lock with a RESET button, two number buttons (0 and 1
    12·1 answer
  • Que rol tiene el ecosistema el patos
    15·1 answer
  • Your manager has asked you to research and recommend a writing guide that examiners in your digital forensics company can use fo
    8·1 answer
  • Calculate the diffusion current density for the following carrier distributions. For electrons, use Dn = 35 cm2/s and for holes,
    6·1 answer
  • The truck travels in a circular path having a radius of 50 m at a speed of v = 4 m>s. For a short distance from s = 0, its sp
    11·1 answer
  • Air, at a free-stream temperature of 27.0°C and a pressure of 1.00 atm, flows over the top surface of a flat plate in parallel f
    13·1 answer
  • When measuring a Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 Inches plus four notches, and the dial re
    13·1 answer
  • An aggregate blend is composed of 55% aggregate A (Sp. Gr. 2.631), 25% aggregate B (Sp. Gr. 2.331) and 20% sand (Sp. Gr. 2.609).
    8·1 answer
  • How many times has the ITU-R revised the CCIR 601 international standard? A. four B. five C. six D. seven
    8·1 answer
  • The regulator is closed when the adjusting screw is turned in (clockwise).
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!