Answer: Advertising acts in a method similar to a fee. People who watch TV broadcasts must watch ADs. TV stations turn this into money by selling airtime to advertisers.
Explanation:
A non-rival good is a good whose consumption by one person does not reduce the remaining quantity available. An example is a street light.
For non-excludable goods, it is impossible to prevent everyone from enjoying the benefits of the good. An example is a lighthouse. This is where the free rider problem comes in.
A free rider is someone enjoying the benefits of a good without paying for it. When a good is both non-rival and non-excludable, it is convenient for consumers to enjoy the benefit without paying for it.
If TV broadcasts are both non-rival and non-excludable, everybody can choose to become a free rider. Advertising can solve this problem by converting free riders to potential buyers of goods or services advertised during broadcasts. This way, stations can generate revenue by selling airtime.
Answer:
The coefficient of thermal expansion tells us how much a material can expand due to heat.
Explanation:
Thermal expansion occurs when a material is subjected to heat and changes it's shape, area and volume as a result of that heat. How much that material changes is dependent on it's coefficient of thermal expansion.
Different materials have different coefficients of thermal expansion (i.e. It is a material property and differs from one material to the next). It is important to understand how materials behave when heated, especially for engineering applications when a change in dimension might pose a problem or risk (eg. building large structures).
Answer:
a) 28 stations
b) Rp = 21.43
E = 0.5
Explanation:
Given:
Average downtime per occurrence = 5.0 min
Probability that leads to downtime, d= 0.01
Total work time, Tc = 39.2 min
a) For the optimum number of stations on the line that will maximize production rate.
Maximizing Rp =minimizing Tp
Tp = Tc + Ftd
At minimum pt. = 0, we have:
dTp/dn = 0
Solving for n²:
The optimum number of stations on the line that will maximize production rate is 28 stations.
b) 
Tp = 1.4 +1.4 = 2.8
The production rate, Rp =
The proportion uptime,
Explanation:
volume = πR²h/3
= πx35²x50/3
= 192325/3
= 64166.725
number of layers n = 50mm/0.05
n = 1000layers
average volume = 64166.725/1000
= 64.167mm³
average area = 64.167/0.05
= 1283.34mm²
average time = 1283.34/900mm x 0.22
= 6.48
6.48 + 15 seconds
= 21.48 seconds
time required = 1000x21.48
= 21480 seconds
convert to minutes
21480/60
= 358 minutes
21480/3600
= 5.967 hours
Answer:
h = 10,349.06 W/m^2 K
Explanation:
Given data:
Inner diameter = 3.0 cm
flow rate = 2 L/s
water temperature 30 degree celcius
at 30 degree celcius 
Re = 106390
So ,this is turbulent flow
SOLVING FOR H
WE GET
h = 10,349.06 W/m^2 K
