Answer:
The overflow rate is 4.24×10^-4 m/s.
The detention time is 7069.5 s
Explanation:
Overflow rate is given as volumetric flow rate ÷ area
volumetric flow rate = 0.3 m^3/s
area = πd^2/4 = 3.142×30^2/4 = 706.95 m^2
Overflow rate = 0.3 m^3/s ÷ 706.95 m^2 = 4.24×10^-4 m/s
Detention time = volume ÷ volumetric flow rate
volume = area × depth = 706.95 m^2 × 3 m = 2120.85 m^3
Detention time = 2120.85 m^3 ÷ 0.3 m^3/s = 7069.5 s
Answer:
1839
Explanation:
the first huge step in solar penal technology came when alxendare becquerel observed the photovolatic effect in 1839,which occurs when a material produces electric current when exposed to light.it was not untill 1888 that the first solar cell was actually built by aleksander stoletov.
<h3>
Answer:</h3><h3><em>1. Ask questions</em></h3><h3><em>2. Thank the interviewer for their time </em></h3><h3>
Explanation:</h3>
1<em>. When the interviewer asked if you have any questions at the end of the interview don't say no. You should always say yes your interviewer is expecting you to ask a few good questions before ending the interview. </em>
<h3><em /></h3>
<em>2. Always thank the interviewer for their time and effort to interview you. This would look very good for you and its a nice way to help wrap up the interview. </em>
Answer:
Code is given below:
Explanation:
.data
str1: .space 20
str2: .space 20
msg1:.asciiz "Please enter string (max 20 characters): "
msg2: .asciiz "\n Please enter string (max 20 chars): "
msg3:.asciiz "\nSAME"
msg4:.asciiz "\nNOT SAME"
.text
.globl main
main:
li $v0,4 #loads msg1
la $a0,msg1
syscall
li $v0,8
la $a0,str1
addi $a1,$zero,20
syscall #got string to manipulate
li $v0,4 #loads msg2
la $a0,msg2
syscall
li $v0,8
la $a0,str2
addi $a1,$zero,20
syscall #got string
la $a0,str1 #pass address of str1
la $a1,str2 #pass address of str2
jal methodComp #call methodComp
beq $v0,$zero,ok #check result
li $v0,4
la $a0,msg4
syscall
j exit
ok:
li $v0,4
la $a0,msg3
syscall
exit:
li $v0,10
syscall
methodComp:
add $t0,$zero,$zero
add $t1,$zero,$a0
add $t2,$zero,$a1
loop:
lb $t3($t1) #load a byte from each string
lb $t4($t2)
beqz $t3,checkt2 #str1 end
beqz $t4,missmatch
slt $t5,$t3,$t4 #compare two bytes
bnez $t5,missmatch
addi $t1,$t1,1 #t1 points to the next byte of str1
addi $t2,$t2,1
j loop
missmatch:
addi $v0,$zero,1
j endfunction
checkt2:
bnez $t4,missmatch
add $v0,$zero,$zero
endfunction:
jr $ra
