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Romashka [77]
3 years ago
9

em 4:A water jet strikes normal to a xedplate. If diameter of the outlet of the nozzle is 8 cm,and velocity of water at the outl

et is 10 m/s, calculate force required to keep the plate in place [25 points]
Engineering
1 answer:
NeX [460]3 years ago
7 0

Answer:

The force required to keep the plate in place is 251.36 N

Explanation:

Force = pressure × area

diameter (d) of the outlet of the nozzle = 8 cm = 8/100 = 0.08 m

area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2

velocity of water (v) at the outlet = 10m/s

height (h) of water at the outlet = v^2/2g = 10^2/2×9.8 = 100/19.6 = 5.102 m

pressure = height × density of water × g = 5.102×1000×9.8 = 49999.6 N/m^2

Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N

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You leave your house at 5:02 PM and run 20 yards down the street. You don't realize that you forgot your Wallet back at home and
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Answer:

The average velocity is 0.203 m/s

Explanation:

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initial displacement, x₁ = 20 yards = 18.288 m

final displacement, x₂ = ¹/₃ x 18.288 = 6.096 m

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7 0
3 years ago
A solid circular rod that is 600 mm long and 20 mm in diameter is subjected to an axial force of P = 50 kN The elongation of the
Kay [80]

Answer:

a) V = 0.354

b)  G = 25.34 GPA

Explanation:

Solution:

We first determine Modulus of Elasticity and Modulus of rigidity

Elongation of rod ΔL = 1.4 mm

Normal stress, δ = P/A

Where P = Force acting on the cross-section

A = Area of the cross-section

Using Area, A = π/4 · d²

= π/4 · (0.0020)²  = 3.14 × 10⁻⁴m²

δ = 50/3.14 × 10⁻⁴    = 159.155 MPA

E(long) = Δl/l  = 1.4/600 = 2.33 × 10⁻³mm/mm

Modulus of Elasticity Е = δ/ε

= 159.155 × 10⁶/2.33 × 10⁻³    = 68.306 GPA

Also final diameter d(f) = 19.9837 mm

Initial diameter d(i) = 20 mm

Poisson said that V = Е(elasticity)/Е(long)

= -  <u>( 19.9837 - 20 /20)</u>

        2.33 × 10⁻³                  

= 0.354,

∴ v = 0.354

Also G = Е/2. (1+V)

=  68.306 × 10⁹/ 2.(1+ 0.354)

= 25.34 GPA

⇒ G = 25.34 GPA

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