Answer:
Explanation:
There are three points in time we need to consider. At point 0, the mango begins to fall from the tree. At point 1, the mango reaches the top of the window. At point 2, the mango reaches the bottom of the window.
We are given the following information:
y₁ = 3 m
y₂ = 3 m − 2.4 m = 0.6 m
t₂ − t₁ = 0.4 s
a = -9.8 m/s²
t₀ = 0 s
v₀ = 0 m/s
We need to find y₀.
Use a constant acceleration equation:
y = y₀ + v₀ t + ½ at²
Evaluated at point 1:
3 = y₀ + (0) t₁ + ½ (-9.8) t₁²
3 = y₀ − 4.9 t₁²
Evaluated at point 2:
0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²
0.6 = y₀ − 4.9 t₂²
Solve for y₀ in the first equation and substitute into the second:
y₀ = 3 + 4.9 t₁²
0.6 = (3 + 4.9 t₁²) − 4.9 t₂²
0 = 2.4 + 4.9 (t₁² − t₂²)
We know t₂ = t₁ + 0.4:
0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)
0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))
0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)
0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)
0 = 2.4 − 3.92 t₁ − 0.784
0 = 1.616 − 3.92 t₁
t₁ = 0.412
Now we can plug this into the original equation and find y₀:
3 = y₀ − 4.9 t₁²
3 = y₀ − 4.9 (0.412)²
3 = y₀ − 0.83
y₀ = 3.83
Rounded to two significant figures, the height of the tree is 3.8 meters.
Answer: Weight on Mars = 0.02593N
Explanation:
Given; Circumference C of Sphere = 70cm = 0.7m,
Specific Gravity S. G. of material = 1.21,
acceleration due to gravity in the Mars gm = 3.7m/s^2
We know that Weight W = mass m × acceleration due to gravity.
Let the Weight in on the Mars be Wm.
Wm = m × gm
Since we are given gm, we need to calculate for m. (Note that mass m is the same everywhere)
But mass = specific gravity × volume
Since we know the specific gravity, let's go ahead to calculate for the volume of the ball.
We know that Volume of a Sphere V = (4/3)πr^3
To get r, we know that C = 2πr
Therefore, r = C/(2π) = 0.7/(2π) = (7/10)/2π = 7/20π (in meters)
V = (4/3)*π×(7/20π)^3 = 343/6000π^2 (in meter^3)
m = 343/6000π^2 × 1.21 = 7.01×10^(-3)kg
Wm = 7.01×10^(-3) × 3.7 = 0.02593N
Answer:
a ship is a large vessel intended for oceangoing or at least deep-water transport, and a boat is anything else." Basically, a ship can carry a boat, but a boat cannot carry a ship
Answer:
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