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BlackZzzverrR [31]
3 years ago
9

Which of the statements about the graph is true? :((

Mathematics
2 answers:
salantis [7]3 years ago
7 0

Answer: D / none are true

Since it's proportional (it's a straight line), B and C are automatically wrong. A would seem true at first glance, <u>BUT </u>if you look closely at the graph, the slope of the graph is actually 2x.

Look at the beginning of the line. It starts at 18 (x = 0/y intercept) and at x = 1, you can see that y is at 16. The y value goes down by 2 every time x increases by 1. This means that the equation of the graph is -2x + 18 = y.

The graph is proportional and has an equation of y = -2x + 18. This means that A, B and C are incorrect.

nika2105 [10]3 years ago
3 0

Answer:

<h3><u><em>Your answer is D. </em></u></h3>

Step-by-step explanation:

It is a straight line also known as <u><em>proportional</em></u>. The first impression, <em><u>A</u></em> appears to be accurate, but closer inspection reveals that the graph's slope is actually <em><u>2x. 18 (x = 0/y intercept) and ends at x = 1, where little y is at 16.</u></em> Any time <em><u>x expands by one, the y value falls by two</u></em>. This says that the <em><u>graph's equation</u></em> is <em><u>-2x + 18 = y.</u></em>

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2a^2b^3 and -4a^2b^3 are like terms true or false
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36 is what percent less than 48?
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Alex plans to invest $6000 for 10 years. Determine how much each investment would be worth to Alex as the CD matures.
34kurt

Answer:

Step-by-step explanation:

A. The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the amount of money deposited.

P represents the principal or amount of money deposited.

R represents interest rate on the deposit.

T represents the duration of the deposit in years.

From the information given,

P = $6000

R = 5%

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B. We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

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P = 6000

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A = P x e^(r x t)

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Therefore,

A = 6000 x e^(0.048 x 10)

A = 6000 x e^(0.48)

A = $9696

4 0
3 years ago
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