Question

A chemist prepares a solution of magnesium fluoride MgF2 by measuring out 0.0113μmol of magnesium fluoride into a 450.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /mmolL of the chemist's magnesium fluoride solution. Round your answer to 3 significant digits.

Answer 1

Answer:

2.51x10⁻⁵ mmol MgF2/L

Explanation:

To find the concentration in mmol / L we need to convert μmol to mmol (1000μmol / 1mmol) and mL to Liters (1000mL / 1L) as follows:

μmol MgF2:

0.0113μmol MgF2 * (1mmol / 1000μmol) = 1.13x10⁻⁵ mmol MgF2

Liters solution:

450mL * (1L / 1000mL) = 0.450L

Concentration in mmol/L:

1.13x10⁻⁵ mmol MgF2 / 0.450L =

2.51x10⁻⁵ mmol MgF2/L