There are zero number of methylene groups in the substance 2,4-dimethylhexane. Methylene groups are the part of a molecule that contains a carbon atom that has a double bond or =CH. Looking at the structure of 2,4-dimethylhexane, you cannot see any carbon atom that has a double bond.
<h3>Answer:</h3>
Potassium has the largest atomic radius.
<h3>Explanation:</h3>
Using periodic table trends one can easily compare the atomic radii of elements. The trends in atomic radii are as follow,
Trends in Groups:
Moving from top to bottom along the groups the atomic radii increases because as you move from top to bottom the number of shells increases hence, the distance of valence electrons from nucleus also increases and therefore, atomic radius increases.
Trends is Periods:
Moving from left to right along the periods the atomic radii decreases. This is because the number of protons and electrons increases but the the valence shell remain the same hence, causing more nuclear charge and more attraction between the valence electrons and nucleus.
<h3>Result:</h3>
Potassium, Calcium, Cobalt and Nickle all are present in same period. Potassium present at the extreme left will have greater atomic radii of 0.227 nm while Co and Ni at the middle of period will have atomic radii of 0.125 nm each. While, the atomic radius of Calcium next to K is 0.197 nm.
Answer:
10.8 g
Explanation:
<em>A chemist adds 480.0 mL of a 0.169 mol/L aluminum chloride solution to a reaction flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Volume of the solution: 480.0 mL
- Concentration of the aluminum chloride solution: 0.169 mol/L
Step 2: Calculate the moles of aluminum chloride in the solution
We will multiply the volume of the solution by the molarity.
0.4800 L × 0.169 mol/L = 0.0811 mol
Step 3: Calculate the mass corresponding to 0.0811 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
0.0811 mol × 133.34 g/mol = 10.8 g
It determine Gibbs free energy
