Answer:
im on the same thing on usa test prep lol i need help too
Explanation:
Answer:
V=1.18 L
Explanation:
Alternative solution:
Calculate how many moles
2.34
g
C
O
2
is
2.34
g
⋅
1
m
o
l
44
g
C
O
2
=
0.053
m
o
l
Simple mole ratios tell us that
1
mol of any gas at STP is
22.4
L
, but since we only have
0.053
m
o
l
, we times
22.4
L
m
o
l
by
0.053
m
o
l
.
22.4
L
m
o
l
⋅
0.053
m
o
l
=
1.18
L
Answer link
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Explanation:
10 valence electron are there
Answer:
0.5ppm
Explanation:
Step 1:
Data obtained from the question.
Volume of water = 2500L
Mas of Cu = 1.25 g
Step 2:
Determination of the concentration of Cu in g/L. This is illustrated below:
Volume of water = 2500L
Mas of Cu = 1.25 g
Conc. of Cu In g/L =?
Conc. g/L = Mass /volume
Conc. of Cu in g/L = 1.25/2500
Conc. of Cu in g/L = 5x10^–4 g/L
Step 3:
Conversion of the concentration of Cu in g/L to ppm. This is illustrated below
Recall:
1g/L = 1000mg/L
Therefore, 5x10^–4 g/L = 5x10^–4 x 1000 = 0.5mg/L
Now, we know that 1mg/L is equal to 1ppm.
Therefore, 0.5mg/L is equivalent to 0.5ppm
