Can somebody please help
1 answer:
You might be interested in
Answer:
HERES YOUR ASSIGNMENT! I EDITED IT ON MICROSOFT SO THAT I CAN SCREENSHOT IT AND SEND IT TO YOU...I HOPE IT HELPS :)
<h3>ARIGATO OZAIMASU!!!</h3>
The tension in the cable is given by the newton's first law will be 163.622 N.
<h3>What is newton's first law?</h3>The summation of the force is equal to zero.
The formula is given as
ΣF = 0
Where m is the mass of the body and a is the acceleration.
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.
Then the tension in the cable will be
Let T be the tension in the cable.
T sin 29° + T sin 53° – 210 = 0
On simplifying, we have
T (sin 29° + sin 53°) = 210
T = 163.622 N
More about the newton's first law link is given below.
#SPJ1
