The bisector of angle APQ passes through O and this is illustrated below.
<h3>How to illustrate the information?</h3>
From the information given, the center is O. and the circle passes through O and cuts at K.
In this case, it should be noted that the circles are equal according to the SAS test.
Here, AOB + APQ = 180° (Linear pair)
2AOB = 180
AOB = 90.
Therefore, the bisector of angle APQ passes through O.
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Answer:
Step-by-step explanation:
First we multiply x through (y+1). This equals xy +x.
Second we take 3 through (y+1). This equals 3y+3.
Next we take xy + x through (x+2). This equals 2x squared, y + 2x squared.
Fourth we take 3y+3 through (x+2). This equals 6xy + 6x.
2y=10x-14
5x-y=7
Divide both sides by 2 in the 1st equation
y=5x-7
Now substitute is to 2nd equation
5x-5x+7=7
0=0
Therefore there is no solution or it is inconsistent