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Svetlanka [38]
3 years ago
8

Fred went to an arcade to play video games. He paid $2 for every 11 tokens he bought. He spent a total of $16 on tokens. Which e

quation can be used to determine t, the number of tokens Fred bought?
Mathematics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Since there are two types of values here: tokens and dollars, we will need to use the same value across numerators and denominators in the ratio.

Choice D has 11 tokens over $2 equals to t tokens over $16. In both fractions the numerator is tokens and denominator is dollars.

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All you need to do is add all 7 job hours, and divide the total by 7. Your answer should be 7
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3 years ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

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Evaluate the quotient

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This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

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The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

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See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

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4 0
1 year ago
Given the graph, find the distance of GH. Round to the nearest tenth.
lord [1]

Answer:

GH = 6.3 units

Step-by-step explanation:

Assuming that 1 box represents 1 unit, the coordinate pair of G = (-2, -3), while H = (0, 3).

Distance between G and H = d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(0, 3) = (x_2, y_2)

GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}

GH = \sqrt{(2)^2 + (6)^2}

GH = \sqrt{4 + 36} = \sqrt{40}

GH = 6.3 units (nearest tenth)

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3 years ago
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