Question

An aqueous solution contains

Answer 1

The mole fraction of KCl = 0.105

Further explanation

Given

%w/w KCl = 32.7

Required

the mole fraction of KCI

Solution

For 100 g solution : KCl = 32.7 g, H₂O = 67.3 g

mol KCl :

$\tt \dfrac{32.7}{74.55~g/mol}=0.439$

mol H₂O :

$\tt \dfrac{67.3}{18.016}=3.74$

total mol of solution = 0.439+3.74=4.179

mol fraction of KCl :

$\tt \dfrac{0.439}{4.179}=0.105$