Answer: Three groups bound to it with no lone pairs
i think...
The temperature of the gas sample is 813 K.
<u>Explanation:</u>
We have to use the ideal gas equation to find the temperature of the gas sample.
The ideal gas equation is PV = nRT
Pressure, P = 429 mm Hg = 0.56 atm
Volume, V = 560 mL = 0.56 L
R = gas constant = 0.08205 L atm mol⁻¹K⁻¹
Mass = 0.211 g
Molar mass of carbon di oxide = 44.01 g / mol
Moles, n = 
= 0.0047 mol
Now, we have to plugin the above values in the above equation, we will get the temperature as,

T = 
= 813 K
So the temperature of the gas sample is 813 K.
Answer:
<h2>Speed = 5.107 mile/hr</h2>
Explanation:
<h3>Given:</h3>
<u>distance</u> =50m = 0.0311 mile
<u>Time</u>= 21.93 seconds/3600 =0.00609 hour
<u>Speed</u><u>=</u>?
<h3>
Speed= Distance / Time </h3><h3>
= 0.0311 / 0.00609</h3><h3>
= 5.107 mile/hr</h3>
Answer:
Explanation:
count given by old sample = .97 disintegrations per minute per gram
count given by fresh sample = 6.68 disintegrations per minute per gram
Half life of radioactive carbon = 5568 years
rate of disintegration
dN / dt = λ N
In other words rate of disintegration is proportional to no of radioactive atoms present . As number reduces rate also reduces .
Let initial no of radioactive be N₀ and after time t , number reduces to N
N₀ / N = 6.68 / .97
Now



λ is disintegration constant
λ = .693 / half life
= .693 / 5568
= .00012446 year⁻¹
Putting the values in the equation above


1.929577 = .00012446 t
t = 15503.6 years .