The position vector of the bullet has components
The bullet hits the ground when , which corresponds to time
:
The bullet travels 168 m horizontally, which would require a muzzle velocity such that
Which part of an atom is mostly empty space?
1 answer:
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Answer:
principal stresses :б1 = 32.62mPa б2 = 31.38mPa
Max Shear stress : 16.31 mPa
Orientation of max principle plane = 44.43°
Orientation of minimum principal plane = 134.43°
Explanation:
Given data:
Torque = 50 N-m
weight = 80 kgs
half of weight is subjected to each leg
radius of bone = 10 mm = 0.010 m
<u>a) Determine the principal stresses and shear stress</u>
first calculate the max shear stress ( this will occur in the outermost element
= 16T / π*d^3 where : T = 50 , d = 0.020 m
hence max shear stress = 32 mPa
next determine compressive stress
= ( 40*g) / π/4*d^2 . where : d = 0.020 m , g = 9.81
hence compressive stress = 1.24 mPa
draw and calculate the radius of Mohr's circle
radius of Mohr's circle = 32.0060
Hence principal stresses = 32.0060 ± 0.62
б1 = 32.62mPa
б2 = 31.38mPa
attached below is the remaining part of the solution
The frictional force between two surfaces is given by:
where
is the coefficienct of friction
is the force with which one surface is pushed against the other one
Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction (for instance, by making the surfaces more "rough"
2) by increasing, the force with which one surface is pushed against the other
Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force
where
Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction
2) by increasing
Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force