r = 7.53 so d = 2r = 2(7.53) = 15.06 cm
Area of square = d^2 / 2 = (15.06)^2 / 2 = 113.41 cm^2
Area of circle = 3.14 (7.53)^2 = 178.04 cm^2
Area of yellow region = Area of circle - Area of square
Area of yellow region = 178.04 cm^2 - 113.41 cm^2
Area of yellow region =64.63 cm^2 = 64.6 cm^2 (nearest tenth)
Answer
64.6 cm^2
Answer:
9: a^8/c^2
Step-by-step explanation:
(a^4/c)^2
(a^8/c^2)
Answer:
x = 11
Step-by-step explanation:
Raising both sides to the fifth power, we get:
27(x - 2) = 3⁵
x - 2 = 3⁵ / 27
x - 2 = 3⁵ / 3³
x - 2 = 3⁽⁵⁻³⁾ = 3² = 9
x = 11
Answer: the diameter of circle b is also less than circle a ?
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
