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Alisiya [41]
3 years ago
7

How many moles are in 3.4 x 10^23 molecules of carbon dioxide CO2

Chemistry
1 answer:
Soloha48 [4]3 years ago
7 0
Moles roughly: 6.02x10^23

3.4x10^23/6.02x10^23 = .565
Rounded to the thousandths
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Answer:

An Arrhenius acid increases the concentration of hydrogen (H+) ions in an aqueous solution, while an Arrhenius base increases the concentration of hydroxide (OH–) ions in an aqueous solution.

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How can understanding atomic light help astronomers determine what planets are composed of?
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The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy. This process utilizes instruments with a grating that spreads out the light from an object by wavelength. This spread-out light is called a spectrum. Every element has a unique fingerprint that allows researchers to determine what it is made of.

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5 0
3 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
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4 0
3 years ago
The conversation of cyclopropane to propene in the gas phase is a first order reaction with a rate constant of 6.7x10-⁴s-¹. a) i
Rus_ich [418]

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b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) concentration after 8.8 min:

8.8\times 60s=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{a-x}

\log\frac{0.25}{a-x}=0.15

\frac{0.25}{a-x}=1.41

(a-x)=0.17M

b) for concentration to decrease from 0.25M to 0.15M

t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\log\frac{0.25}{0.15}\\\\t=\frac{2.303}{6.7\times 10^{-4}s^{-1}}\times 0.20

t=687s

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3 years ago
What is an Ytterbium (Its an element) . in your own words but be more detailed about what you say.
Butoxors [25]

Answer:

Ytterbium is a chemical element with the symbol Yb and atomic number 70. It is the fourteenth and penultimate element in the lanthanide

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3 years ago
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