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lorasvet [3.4K]
3 years ago
11

The triangles below will be used to construct a polygon.

Mathematics
2 answers:
torisob [31]3 years ago
7 0
The answer is heptagon
DIA [1.3K]3 years ago
4 0
I think it’s a heptagon sorry if it’s wrong
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Please help me find the greatest common factor for these 2 problems..
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A greatest common factor is the largest number that goes into two or more numbers (in this case two). To find the GCF of two numbers, we have to find the prime factorization (how to express a number as a product of prime numbers) and then see which numbers are common in both of the prime factorizations.

11. The prime factorization of 12 is 3 * 2 * 2. The prime factorization of 18 is 3 * 3 * 2. Looking at the prime factorizations, we can see that both of them have 3 and 2. That means that the GCF is 3 * 2 which is 6.

12. The prime factorization of 48 is 2 * 2 * 2 * 2 * 3. The prime factorization of 80 is 2 * 2 * 2 * 2 * 5. We see that the numbers shared are 2, 2, 2, and 2. That means that the GCF is 2 * 2 * 2 * 2 or 16.

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3 years ago
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Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

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