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3 years ago

Explain how the understanding of atomic emission led to development of the atomic theory.

1 answer:

6 0

<span>The explanation would take a short course in atomic physics for you to understand it. atomic theory made on the basis of information given in atomic emission.</span>

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Help pls, ty.

Ann [662]

Answer:

According to conservation of matter, there should be equal amounts of all elements on both the reactant and product side.

Reactant:

1 Ca

1 C

1 O

Product:

1 Ca

1 C

3 O

Therefore, your friend is right because the law of conservation of matter is not followed in this chemical equation.

Explanation:

(2)

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2 years ago

Describe how this instrument works.<br><br> Operation:

guapka [62]

Answer:

Microscope

Explanation:

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2 years ago

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Amy's cousins help Andy out and drive him to the soccer field. They travel 15 m/s.

DochEvi [55]

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2 years ago

Emission Vehicle Program Should automobile makers be made to adhere to quotas zero - emission vehicles set by states , even if t

navik [9.2K]

Answer: Zero-emission vehicles have no tailpipe emissions, no emissions from gasoline, and no emission-control systems, which deteriorate over time.

Explanation:

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2 years ago

Using the average initial pH of your acetic acid solutions (2.96), and the average molarity of those solutions(.0602), calculate

Orlov [11]

Answer : The value of Ka for acetic acid is, $2.03\times 10^{-5}$

Explanation :

The chemical formula of acetic acid is, $CH_3COOH$ .

The chemical equilibrium reaction will be:

$CH_3COOH\rightleftharpoons CH_3COO^-+H^+$

Given:

pH = 2.96

First we have to calculate the concentration of hydrogen ion.

$pH=-\log [H^+]$

$2.96=-\log [H^+]$

$[H^+]=1.096\times 10^{-3}M$

That means,

$[H^+]=[CH_3COO^-]=1.096\times 10^{-3}M$

$[CH_3COOH]=0.0602-(1.096\times 10^{-3})=0.0591M$

The expression for reaction is:

$K_a=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}$

$K_a=\frac{(1.096\times 10^{-3})\times (1.096\times 10^{-3})}{0.0591}$

$K_a=2.03\times 10^{-5}$

Thus, the value of Ka for acetic acid is, $2.03\times 10^{-5}$

3 0

3 years ago