Answer:
e
Explanation:
i took it myself and got it right
Answer with Explanation:
We are given that
Diameter=0.030 m
Length of sprue=
=0.200 m
Metal volume flow rate,Q=0.03
Q=
because 1 minute=60 seconds
Let 1 for the top and 2 for the bottom






Pressure at the top and bottom of the sprue is atmospheric

Substitute the values






Reynolds number=


Substitute the values then we get
Reynolds number=
Reynolds number=42525
The Reynolds number is greater than 4000 .Therefore, the flow is turbulent.
1) According to the law of conservation of momentum ..
<span>Horiz recoil mom of gun (M x v) = horiz. mon acquired by shell (m x Vh) </span>
<span>1.22^6kg x 5.0 m/s = 7502kg x Vh </span>
<span>Vh = 1.22^6 x 5 / 7502 .. .. Vh = 813 m/s </span>
<span>Barrel velocity V .. .. cos20 = Vh / V .. ..V = 813 /cos20 .. .. ►V = 865 m/s </span>
<span>2) Using the standard range equation .. R = u² sin2θ /g </span>
<span>R = 865² x sin40 / 9.80 .. .. ►R = 49077 m .. (49 km)</span>
Answer:
Explanation:
Let s be displacement from equilibrium position . Restoring force
m d²s / dt² = - k s
d²s / dt² = - k /m s
Put k /m = ω
d²s / dt² + ω² s = 0
The solution of this differential equation
= s = A cosωt
Now when t = 0 , s = 2 cm
A = 2 cm
Putting the values we have
2 = A cos 0
A = 2 cm
s ( t) = 2 cos ωt