Answer:
No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.
Explanation:
A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.
Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:
* When the diameter and length are comparable (i.e have the same measurement)
When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.
Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.
Acceleration = (change in speed) / (time for the change)
change in speed = (speed at the end) minus (speed at the beginning)
change in speed = (zero) minus (28 m/s) = -28 m/s
Acceleration = (-28 m/s) / (13 sec)
Acceleration = -2.15 m/s²
It is about 95%. The Wechsler Adult Intelligence Scale-IV is an IQ test that is given by therapists and measures worldwide scholarly working. It incorporates both verbal and nonverbal parts. The normal score for all tests and subtests is 100; therefore, a score of more than 100 is better than expected and beneath 100 is underneath normal.
Gravity is a force acting on a object
Answer:a
Explanation:
Given
![[H^+]=5.3\times 10^{-4}\ M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D5.3%5Ctimes%2010%5E%7B-4%7D%5C%20M)
and 
Also ![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
therefore 
Thus 
and ![pOH=-\log [OH^{-}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E%7B-%7D%5D)
![[OH]^{-1}=10^{-10.25}](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D10%5E%7B-10.25%7D)
![[OH]^{-1}=1.88\times 10^{-11}\ M](https://tex.z-dn.net/?f=%5BOH%5D%5E%7B-1%7D%3D1.88%5Ctimes%2010%5E%7B-11%7D%5C%20M)
As the pH is less than 7 therefore solution is acidic
