All categories

3 years ago

After a tree is cut down with a chainsaw, it is impossible to put the tiny wood chips back together

Chemistry

2 answers:

koban [17]3 years ago

7 0

No, even after you cut the tree down, the wood is still wood

Shtirlitz [24]3 years ago

4 0

Answer:

No, because even if you cut the tree into small pieces it’s still a tree.

Explanation:

You might be interested in

Consider the two electron arrangements for neutral atoms A and B. Are atoms A and B the same element? A - 1s2, 2s2, 2p6, 3s1 B -

iogann1982 [59]

✨✨✨✨✨✨✨✨✨✨✨✨

<h2>Technically yes but no because you have to fill the 3s orbital before the 5s orbital</h2>

✨✨✨✨✨✨✨✨✨✨✨✨

3 0

3 years ago

As the pressure on the surface of a liquid decreases, the temperature at which the liquid will boil

enot [183]

Increases with pressure

8 0

3 years ago

Read 2 more answers

2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is.

Andrej [43]

2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is 3,4 dimethyl - 1- pentene.

The reaction of 2-bromo-3,4-dimethylpentane is combined with t-butoxide forms 2 alkene in the elimination reaction due to steric hindrance. The least stable alkene 3,4 dimethyl - 1- pentene is easy to make. the t-butoxide is (CH₃)₃CO⁻. The reaction involves in this reaction is E2 elimination reaction. This reaction involves the one step reaction. The product will also form that is 3,4 dimethyl - 2 - pentene. so the reaction involve Elimination reaction and the product due to steric hindrance is 3,4 dimethyl - 1- pentene

Thus, 2-bromo-3,4-dimethylpentane is combined with t-butoxide. The product of this reaction is 3,4 dimethyl - 1- pentene.

To learn more about t-butoxide here

brainly.com/question/12303978

#SPJ4

4 0

1 year ago

Which nuclei are most useful for organic structure determination using nmr spectroscopy? (select all that apply.)?

Mumz [18]

Hydrogen-1, Carbon-13, Nitrogen-15, Fluorine-19, and Phosphorus-31 are the most useful. Out of these, Hydrogen-1 and Carbon-13 in NMR are the most useful nuclei because the these atoms are the most commonly present in organic molecules.

5 0

3 years ago

A grating has 470 lines/mm. how many orders of the visible wavelength 538 nm can it produce in addition to the m = 0 order?

maria [59]

Three complete orders on each side of the m=0 order can be produced in addition to the m = 0 order.

The ruling separation is

d=1 / (470mm −1) = 2.1×10⁻³ mm

Diffraction lines occur at angles θ such that dsinθ=mλ, where λ is the wavelength and m is an integer.

Notice that for a given order, the line associated with a long wavelength is produced at a greater angle than the line associated with a shorter wavelength.

We take λ to be the longest wavelength in the visible spectrum (538nm) and find the greatest integer value of m such that θ is less than 90°.

That is, find the greatest integer value of m for which mλ<d.

since d / λ = 538×10⁻⁹m / 2.1×10 −6 m ≈ 3

that value is m=3.

There are three complete orders on each side of the m=0 order.

The second and third orders overlap.

Learn more about diffraction here : brainly.com/question/16749356

#SPJ4

7 0

1 year ago