Question

4. A sample of gas has a pressure of 700 mmHg and 30.0°C. Ar what temperature would the pressure be 600 mmHg if the volume remains constant?​

Answer 1

Answer:

T₂  = 259.84 K

T₂  = -13.31 °C

Explanation:

Given data:

Initial pressure = 700 mmHg

Initial temperature = 30.0°C (30+273.15 K = 303.15 K)

Final temperature = ?

Final pressure = 600 mmHg

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

700 mmHg /303.15 K  = 600 mmHg / T₂

T₂  = 600 mmHg × 303.15 K / 700 mmHg

T₂  =181890 mmHg.K /700 mmHg

T₂  = 259.84 K

Temperature in celsius

259.84 K - 273.15 = -13.31 °C