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True [87]
3 years ago
11

What’s the answer to this?

Chemistry
1 answer:
Arturiano [62]3 years ago
5 0

Answer : The balanced chemical reaction will be:

3Ca(s)+2Al(NO_2)_3(aq)\rightarrow 2Al(s)+3Ca(NO_2)_2(aq)

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

When solid calcium metal reacts with aqueous aluminum nitrate then it gives aqueous calcium nitrate and solid aluminium.

The balanced chemical reaction will be:

3Ca(s)+2Al(NO_2)_3(aq)\rightarrow 2Al(s)+3Ca(NO_2)_2(aq)

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The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO
Black_prince [1.1K]
CO₂  +  H₂O  ------->  H₂CO₃

moles of CO₂ = \frac{MASS  of  Carbon}{ MOLAR  MASS}
              
                       = \frac{528  g}{44.01  g / mol}
 
                       =  11.997 mol

mole ratio of  CO₂  :  H₂O  =   1  :  1
           
            ∴ moles of H₂O  =  (`11.997 mol )  *  1
                                       =  11.997 mol
                                       ≈  12  mol
 
6 0
3 years ago
Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation:
nignag [31]

Answer:  1) Maximum mass of ammonia  198.57g  

2) The element that would be completely consumed is the N2

3) Mass that would keep unremained, is the one of  the excess Reactant, that means the H2 with 3,44g

Explanation:

  • In order to calculate the Mass of ammonia , we first check the Equation is actually Balance:

N2(g) + 3H2(g) ⟶2NH3(g)

Both equal amount of atoms side to side.

  • Now we verify which reagent is the limiting one by comparing the amount of product formed with each reactant, and the one with the lowest number is the limiting reactant. ( Keep in mind that we use the  molecular weight of 28.01 g/mol N2; 2.02 g/mol H2; 17.03g/mol NH3)

Moles of ammonia produced with 163.3g N2(g) ⟶ 163.3g N2(g) x (1mol N2(g)/ 28.01 g N2(g) )x (2 mol NH3(g) /1 mol N2(g)) = 11.66 mol NH3

Moles of ammonia produced with 38.77 g H2⟶  38.77 g H2 x ( 1mol H2/ 2.02 g H2 ) x (2 mol NH3 /3 mol H2 ) = 12.79 mol NH3

  • As we can see the amount of NH3 formed with the N2 is the lowest one , therefore the limiting reactant is the N2 that means, N2 is the element  that would be completey consumed, and the maximum mass of ammonia will be produced from it.
  • We proceed calculating the maximum mass of NH3 from the 163.3g of N2.

11.66  mol NH3 x (17.03 g NH3 /1mol NH3) = 198.57 g NH3

  • In order to estimate the mass of excess reagent, we start by calculating how much H2 reacts with the giving N2:

163.3g N2 x (1mol N2/28.01 g N2) x ( 3 mol H2 / 1 mol N2)x (2.02 g H2/ 1 mol H2) = 35.33 g H2

That means that only 35.33 g H2 will react with 163.3g N2 however we were giving 38.77g of  H2, thus, 38.77g - 35.33 g = 3.44g H2 is left

3 0
3 years ago
An electron moved from a higher energy level to a lower energy level. What most likely happened during the transition? (4 points
Alex787 [66]

Answer: The anwser is A a photon was realeased please mark brainliest

Explanation:

6 0
2 years ago
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alex41 [277]

Answer:

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Explanation:

1.24 ml= 0.00124 L

3600 s=1 hr

0.00124 x 3600=4.46

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