The power P(x) carried by this wave at a point x = P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k
Power time is the pace at which work is completed or energy is delivered; it is expressed as the product of the work completed (W) and the energy transferred (t), or W/t. The variation in the gas pressure ΔP measured from the equilibrium value is also periodic with the same wave number and angular frequency as for the displacement which is given by
ΔP = ΔPmax sin (kx−ωt)
Power is an expression of energy expended through time (effort), of which force is an element, as opposed to force itself, which is the fundamental outcome of an interaction between two objects. Power can be measured and described, but a force is a real physical entity, but power is not. The power is the rate at which the piston is doing work on the element at any instant of time is given by
Power = F ⋅ v
As we mention before in the concept session, the power of the wave is given by
P = ρ ν ω² A s² sin(kx-ωt)
P(x) = 1/2 μ ω² ν A²
= 1/2 μ ω² ω/2 A² e⁻²ᵇˣ
P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k
So, The final answer of power P(x) is P(x) = (μ ω³ A² e⁻²ᵇˣ)/2k.
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Answer:
Because of the knowledge of <u>relative size</u>, it will be assumed that the smaller jetliner is farther away.
Explanation:
According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.
As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.
Therefore, the jet that is nearer appears larger.
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Answer:
You don't have to take my word on this, but given that there is less wax on A after heating, it sent the most heat into the wax balls therefore it is a better conductor if heat
Answer
given,
angle with horizontal = 12°
constant speed with the slope = 1 m/s
Work on the skier to move 8 m = 900 J
a) Rope moved with constant speed
change in kinetic energy is equal to zero
work done by the force of the rope = 900 J
rate of force of the rope when skier move with
b) v = 1 m/s total time t = 8 s
Power =
=
= 112.5 W
c) v = 2 m/s total time t = 8/2 = 4 s
Power =
=
= 225 W
Answer:
Explanation:
Given
Tom is on half way between the center and the outer rim
Mary is on the extreme outer rim
Suppose 
is the angular velocity of ride with radius of outer rim be R
angular acceleration of Ride
At any instant both Tom and Mary experience the same angular speed
(b)Linear velocity at any instant
Thus Tom has higher linear speed
(c) For radial Acceleration
Tom has higher radial Acceleration as it is directly Proportional of radius
