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Alik [6]
3 years ago
9

2x2+3x−12, when x=5

Mathematics
1 answer:
lianna [129]3 years ago
5 0
7
Is right I don’t know what the other answer did
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Select the equation in which the graph of the line has a negative slope, and the y-intercept equals 10. Answer 10x + 5y = –25 5x
adoni [48]
The answer is 20x + 5y = 50
If u move the 20x over u get:
5y=-20x + 50

Solve for y by divided by 5

This gets y=-4x + 10

Now the answer is in slope intercept form: the -4 is the slope and 10 is the y-intercept
4 0
4 years ago
What is the slope of the line between (-4, 4) and (-1, -2)?<br> 1<br> 2<br> -2<br> -1
zubka84 [21]

Answer:   -2, which is choice C

Work Shown:

(x_1,y_1) = (-4,4) \text{ and } (x_2,y_2)  = (-1,-2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-2 - 4}{-1 - (-4)}\\\\m = \frac{-2 - 4}{-1 + 4}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

The slope is -2

7 0
2 years ago
A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi
blondinia [14]

Answer:

The required function is: P(x)=-3x^2+78x-360

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is x-6

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

30-3(x-10)

30-3x+30

-3x+60

Where x-10 represents the increase in price and 3  represents the decrease in sales per week.

Thus the profit will be:

P(x)=(x-6)(-3x+60)

P(x)=-3x^2+78x-360

Hence, the required function is: P(x)=-3x^2+78x-360

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: x=\frac{-b}{2a}

Substitute a=-3, b=78 and c=-360 in above.

x=\frac{-78}{2(-3)}=13

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in P(x)=-3x^2+78x-360

P(x)=-3(13)^2+78(13)-360=$147

Hence, the maximum weekly profit is $147

5 0
3 years ago
2x + 3/ x - 4 - 2x - 8/ 2× + 1 = 1
Debora [2.8K]
\dfrac{2x+3}{x-4}-\dfrac{2x-8}{2x+1}=1\ \ \ |the\ domain\ D:x\neq4\ and\ x\neq-\dfrac{1}{2}\\\\\dfrac{(2x+3)(2x+1)}{(x-4)(2x+1)}-\dfrac{(2x-8)(x-4)}{(2x+1)(x-4)}-1=0\\\\\dfrac{4x^2+2x+6x+3}{2x^2+x-8x-4}-\dfrac{2x^2-8x-8x+32}{2x^2+x-8x-4}-\dfrac{2x^2+x-8x-4}{2x^2+x-8x-4}=0\\\\\dfrac{4x^2+8x+3}{2x^2-7x-4}-\dfrac{2x^2-16x+32}{2x^2-7x-4}-\dfrac{2x^2-7x-4}{2x^2-7x-4}=0\\\\\dfrac{4x^2+8x+3-2x^2+16x-32-2x^2+7x+4}{2x^2-7x-4}=0\\\\\dfrac{31x-25}{2x^2-7x-4}=0\iff31x-25=0\\\\31x=25\\\\\boxed{x=\frac{25}{31}}
6 0
3 years ago
If (8^2)p = 8^4, what is the value of p?
den301095 [7]
The answer is 2.
Explantation: 
First, we simplify it to 64^p = 4096.
Then, take the log of both sides:
p = log (4096) / log (64)
p = 2
3 0
3 years ago
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