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Lerok [7]
3 years ago
8

1.) A test has twenty questions worth 100 points. The test consists of True/False questions worth 3 points each and multiple cho

ice questions worth 11 points each. How many multiple-choice questions are on the test?
Equation 1:

Equation 2:
Solution: multiple choice

I have the solution I just need to know how to get the equations
Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

Multiple choice questions = 5

True questions = 15

Step-by-step explanation:

Given that:

Total number of questions = 20

Total worth of point = 100

Multiple choice questions (M) = 11 points each

True false questions (T) = 3 points each

Hence,

M + T= 20 ____(1)

11M + 3T = 100 ____(2)

M = 20 - T

Using the relation in (2)

11(20 - T) + 3T= 100

220 - 11T + 3T= 100

220 - 8T = 100

-8Tf = 100 - 220

-8T = - 120

T = 120/8

T = 15

Mc = 20 - 15

Mc = 5

Multiple choice questions = 5

True false questions = 15

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Step-by-step explanation:

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2 years ago
What is the unit rate of 5 pounds of oranges cost 10.45?<br> find the unit rate
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8 0
3 years ago
The art club held a car wash on Saturday and Sunday. They washed a total of 50 cars. If they washed 30% of the cars on Sunday, h
o-na [289]

Answer:

If I did my math correctly, They washed 15 cars on Sunday.

Step-by-step explanation:

50 cars = 100%

Therefore 1 car would be 2% because 50 is half of 100.

So because 30% would be 2 times the amount of cars, we divide 30 by 2, giving us 30% = <u>15 cars on Sunday</u>

With this information, we can take away 15 from 50 giving us 35 cars which is equal to 70% on Saturday

Here is some extra data:

10% = 5 cars

20% = 10 cars

30% = 15 cars

40% = 20 cars

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60% = 30 cars

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80% = 40 cars

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Basically, every 10% is +5 cars

6 0
3 years ago
Can 15x-10 be factored
Anna [14]
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6 0
4 years ago
Read 2 more answers
A textbook company keeps track of its daily cost for printing whole textbooks to different schools, but can only print up to 500
seraphim [82]
Part A: Chose some value for x, that means any amount of books to print for example 100 books, so x=100
Replace x=100 in C(x) and solve:
C(100)=3.5*100+1200=1550
Part B: Replace C(x) by 1900 and solve for x from the given equation:
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Part C: the statement C(20)=1270 means that 1270 is the cost for printing 20 books.
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8 0
3 years ago
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