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Mathematics

2 answers:

NeX [460]3 years ago

8 0

Answer:

Question it in english

Step-by-step explanation:

valentinak56 [21]3 years ago

6 0

Si yo hablo español

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Simlify with step by step

ad-work [718]

Answer:

Here is your answer

Step-by-step explanation:

√3

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8 0

3 years ago

Read 2 more answers

Let c be the curve of intersection of the parabolic cylinder x2 = 2y, and the surface 3z = xy. find the exact length of c from t

Mandarinka [93]

Parameterize the intersection by setting $x(t)=t$ , so that

$x^2=2y\iff y=\dfrac{x^2}2\implies y(t)=\dfrac{t^2}2$
$3z=xy\iff z=\dfrac{xy}3\implies z(t)=\dfrac{t^3}6$

The length of the path $C$ is then given by the line integral along $C$ ,

$\displaystyle\int_C\mathrm dS$

where $\mathrm dS=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$ . We have

$\dfrac{\mathrm dx}{\mathrm dt}=1$
$\dfrac{\mathrm dy}{\mathrm dt}=t$
$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{t^2}2$

and so the line integral is

$\displaystyle\int_{t=0}^{t=2}\sqrt{1^2+t^2+\dfrac{t^4}4}\,\mathrm dt$

This result is fortuitous, since we can write

$1+t^2+\dfrac{t^4}4=\dfrac14(t^4+4t^2+4)=\dfrac{(t^2+2)^2}4=\left(\dfrac{t^2+2}2\right)^2$

and so the integral reduces to

$\displaystyle\int_{t=0}^{t=2}\frac{t^2+2}2\,\mathrm dt=\dfrac{10}3$

3 0

3 years ago

Consider the system of linear equations y=3x+5 y=Mx+b Which values an M & B will create a system of linear equations with no

OLEGan [10]

Answer:

value of 'm' equal to 5 will produce no solution as they'll be parallel lines

value of 'b' equal to 5 will produce no solution because it will be the same line

Step-by-step explanation:

5 0

3 years ago

HELP!

kondor19780726 [428]