3 years ago

I need help Ill give brainlyiest

Mathematics

1 answer:

Crank3 years ago

3 0

1: 1
2: 1
3: 5
4: -8
5: 1
6: 1
7: 3
8: 10

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Caitlyn did 6/7 of the problems on her quiz correctly and 4 incorrectly. She did all the problems. How many problems were there?

vazorg [7]

It's simple you've been told that correct answers equals 6/7 and she did all the questions. Therefore the incorrect answers equals 1/7, which is 4. So just times 4 by 7. 4 x 7 = 28. 28 questions on the quiz.

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3 years ago

Solve 31-X + (2 x + 1)] = x - 1.

Kobotan [32]

Answer:

x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)

Step-by-step explanation:

31 - X + (2x+1) = x - 1

or, 2x+1 = x - 1 - 31 + X

or, 2x - x = -1 -31 + X -1

or, x = -2 -31 + X

or, x = X - 33

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2 years ago

100x^2-4=0<br> quick pls with all work

Finger [1]

4(5x+1)(5x-1) = 0

1. Take out the GCF (in this case, 4)
4(25x^2-1) = 0

2. This can be further factored. Factor the values within the parenthesis
4(5x + 1)(5x -1) = 0

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2 years ago

Read 2 more answers

Find quadratic polynomial which best fits the function f(x)=e^x and x=0, in the sense that g(0)= f(0), and g'(0) = f'(0), and g"

Dmitriy789 [7]

Let $g(x)=ax^2+bx+c$ . Then

$\begin{cases}g(0)=c\\g'(0)=b\\g''(0)=2a\end{cases}$

Meanwhile, since $f(x)=e^x$ , you have $f(0)=f'(0)=f''(0)=e^0=1$ .

It follows that $a=\dfrac12$ , $b=1$ , and $c=1$ , so that the quadratic fit for $f(x)=e^x$ that satisfies the given points is

$g(x)=\dfrac12x^2+x+1$

Note that this is just the second-order Taylor polynomial for $e^x$ about $x=0$ .

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3 years ago

What is the equation of the line that passes through the point (7,-6)(7,−6) and has a slope of -2−2?

kari74 [83]

Is the slope really -2-2? Or is that a miss type?

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2 years ago