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shutvik [7]
3 years ago
15

A sailboat set a course of N 23° E from a small port along a shoreline that runs north and south. Sometime later the boat overtu

rned and the crew sent out a distress call. They estimated that they were 11 miles away from the nearest harbor, which is 28 miles north of the port they had set sail from. If a rescue team leaves from the harbor, find all possible courses the team must follow in order to reach the overturned sailboat. (Select all that apply.)
A.) S 73° E

B.) N 73° E

C.) S 29° E

D.) S 17° E

E.) S 61° E
Mathematics
2 answers:
xeze [42]3 years ago
7 0
A S 72* if u add the 23 and 28 and then divide then plus
mina [271]3 years ago
4 0

Answer:

Step-by-step explanation:

The answer is 5cwlcusid because it has a more angle to the attraction

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What is the slope help pls?
almond37 [142]

Answer:

7

Step-by-step explanation:

7 0
3 years ago
You are studying for your final exam of the semester. up to this point,you recieved 3 exam scores of 83%,85%, and 84%. to reciev
tamaranim1 [39]
<span>[68,100]

This will allow you to get a B score.

To solve find the medium by adding the values divided by 4, solve for the unknown of the final exam, with the minimum value equalling 80, this will give you 68.</span>
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3 years ago
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A boat travels 12 km upstream and back in 1 hour 45 minutes. If the speed of the current is 3 km/h throughout, find the speed of
Elza [17]

Answer:

14.3 km/h   to 3 significant figures

Step-by-step explanation:

Let time travelling upstream be t1 hours and downstream = t2 hours.

t1 + t2 = 1.75..........................(1)

Let v  be the speed of the boat in still water.

12 / t1 = v - 3.........................(2)

12 /  t2 = v + 3........................(3)

From (1) and (3) , substituting for t2:-

12 / (1.75 - t1) = v + 3 ..................(4)

Subtract:-   (2) - (4):-

12 / t1 - 12 / (1.75 - t1) = -6

12(1 .75 - t1) - 12t1 = -6t1(1.75 -  t1)

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Therefore the speed in still water (v)  = 12/1.058 + 3 = 14.3 to 3 sig figs

3 0
3 years ago
What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?
Morgarella [4.7K]
Geometric is
a_n=a_1r^{n-1}
an=nth term
a1=first term
r=common ratio
n=which term

commmon ratio is like
a1 times r=a2
4 to 8
4 times 2=8
r=2
first term is 4
therefor

a_n=4(2)^{n-1}
the nth term is 4(2)^{n-1}




3 0
4 years ago
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