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aleksley [76]
3 years ago
14

The following inequalities are equivalent except ... A <3 B −1<2 C +1<3 D −2<1

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

C + 1 < 3 is not equivalent.

Step-by-step explanation:

B - 1 < 2 ⇒ B < 3

C + 1 < 3 ⇒ C < 2

D - 2 < 1 ⇒ D < 3

Therefore, all inequalities are equivalent except C + 1 < 3.

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2n+(7n+8)= what is the missing coefficient
Taya2010 [7]

Assuming that you were to simplify this, you'd get 2n + 7n + 8 = 9n + 8.

6 0
3 years ago
It says the number e is a famous irrational number and is one of the most important numbers in mathematics the number e approxim
makkiz [27]
Well you could round it to the 4th decimal, which would be 2.7183
That as a mixed number would be  2\frac{7183}{10000} or as an improper fraction \frac{27183}{10000}
7 0
4 years ago
Find cos(B) in the triangle.<br> Choose 1 answer: 8/17
gavmur [86]

Answer:

8 / 17

Step-by-step explanation:

So cosine is adjacent ÷ hypotenuse.

Adjacent = 8

Hypotenuse = 17

8 / 17

7 0
4 years ago
Factor 9x^2+66xy+121y^2
Korvikt [17]
Answer: (3x + 11y)^2

Demonstration:

The polynomial is a perfect square trinomial, because:

1) √ [9x^2] = 3x

2) √121y^2] = 11y

3) 66xy = 2 *(3x)(11y)

Then it is factored as a square binomial, being the factored expression:

 [ 3x + 11y]^2

Now you can verify working backwar, i.e expanding the parenthesis.

Remember that the expansion of a square binomial is:

- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2

=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.

7 0
4 years ago
Let a be an mn matrix, and let u and v be vectors in irn with the property that au = 0 and av = 0. explain why a(u + v) must be
tatiyna
\mathbf{Au}=\mathbf0
\mathbf{Av}=\mathbf0

\implies\mathbf{Au}+\mathbf{Av}=\mathbf0
\implies\mathbf A(\mathbf u+\mathbf v)=\mathbf0

Multiplying by scalars c,d won't change this fact.
4 0
4 years ago
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