If you double the radius of the earth and keep the mass of the earth the same, the acceleration of gravity on the surface of the
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Height of the waterfall is 0.449 m
its horizontal distance will be 2.1 m
now let say his speed is v with which he jumped out so here the two components of his velocity will be
here the acceleration due to gravity is 9.81 m/s^2 downwards
now we can find the time to reach the other end by y direction displacement equation
also from x direction we can say
now we have
we will plug in this value into first equation
now as we know that
t = 0.63 s
so his minimum speed of jump is 4.1 m/s