All categories

2 years ago

What are the three main parts that make up GAIA? Briefly explain and describe each.

Physics

2 answers:

Lorico [155]2 years ago

6 0

Answer:

The Gaia spacecraft is composed of two sections: the Payload Module and the Service Module. The Payload Module is housed inside a protective dome and contains the two telescopes and the three science instruments. They are all mounted on a torus made of a ceramic material (silicon carbide).

Explanation:

Hope this helps, Have a Great Day!!

jeka57 [31]2 years ago

3 0

Answer:

GAIA is composed of three main parts; the astrometry instrument, the photometric instrument, and the radial-velocity spectrometer. The astrometry instrument is used to determine the angular positions of stars to better measure their distances and motions. The photometric instrument measures the luminosity of stars to help determine stellar properties such as temperature, mass, age, and what elements the stars are made up of. The radial-velocity spectrometer will determine the speed of galactic objects along the line of sight.

Explanation:

You might be interested in

A train travels 120 km in 2 hours and 30 minutes. What is its average speed?

ivann1987 [24]

Answer:

13.33 or 13 1/3m/s (meters per second)

Explanation:

In physics, we use the basic units of meters and seconds. So first convert (km) into meters (m) and also hours and minutes into seconds (s). We end up with 120000m and 9000s. Then divide the 120000m by the 9000s and you end up with 13.33 or 13 1/3 m/s.

5 0

2 years ago

Read 2 more answers

How long would this acceleration last

Aleksandr-060686 [28]

It would last as long as the applied force continued, or until the accelerating object hit something.

6 0

2 years ago

What causes an object to rotate

frez [133]

A spinning force acting upon it

3 0

2 years ago

Charge is distributed uniformly on the surface of a large flat plate. the electric field 2 cm from the plate is 30 n/c. the elec

AysviL [449]

The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
$E= \frac{\sigma}{2\epsilon_0}$
where
$\sigma$ is the charge density
$\epsilon_0$ is the vacuum permittivity

We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
$E=30 N/C$

7 0

2 years ago

Apparent brightness depends on which two properties?

Serjik [45]

Answer:

I believe it is luminosity and distance

Explanation:

So B

6 0

2 years ago

Read 2 more answers