Angular momemtum : mass * tangential speed * distance to the center = 50*2.1*3.6=37800 J.s
Newtons first law of motion is also known as the law of inertia
Answer:
a) v = 141.9 m/s
b) v = 317.4 miles/h
Explanation:
a) How fast was he moving in meters per second?

Hence, the jet ski is moving at 141.9 meters per second.
b) How fast was he moving in miles per hour?
Therefore, the jet ski is moving at 317.4 miles per hour.
I hope it helps you!
Answer:
False
Explanation:
False, as a magnetic field is generated whenever current travels through a conductor.
An electromagnet consists of a coil of wire wrapped around a bar of iron. The coil and iron bar get magnetized when electric current flows through the wire. An electromagnet also has north and south magnetic poles. The magnetic field is strongest at either pole of the magnet.
<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2><h2 /><h2>

</h2><h2>
_____________________________________</h2>
<h2>DATA:</h2>
mass = m = 2kg
Distance = x = 6m
Force = 30N
TO FIND:
Work = W = ?
Velocity = V = ?
<h2>
SOLUTION:</h2>
According to the object of mass 2 kg travels a distance when the force was exerted on it. The graph between the Force and position was plotted which shows that 30 N of force was used to push the object till the distance of 6.0m.
To find the work, I will use the method of determining the area of the plotted graph. As the graph is plotted in the straight line between the Force and work, THE PICTURE ATTCHED SHOWS THE AREA COVERED IN BLUE AS WORK DONE AND HEIGHT AS 30m AND DISTANCE COVERED AS 6m To solve for the area(work) of triangle is given as,

Base is the x-axis of the graph which is Position i.e. 6m
Height is the y-axis of the graph which is Force i.e. 30N
So,

W = 90 J
The work done is 90 J.
According to the principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.



<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>