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3 years ago

What is the name of the compound br8P4

Physics

1 answer:

vlada-n [284]3 years ago

6 0

Answer:

Octabromine tetraphosphide

Explanation:

This compound has in its formula:

- Eight bromines

- Four phosphorous

8 → octa prefix

4 → tetra prefix

Right answer is Octabromine tetraphosphide

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A 7.25-kg bowling ball is being swung horizontally in a clockwise direction (as viewed from above) at a constant speed in a circ

MaRussiya [10]

Answer:

$a_c=9.66\frac{m}{s^2}$

Explanation:

The centripetal acceleration is given by:

$a_c=\frac{v^2}{r}(1)$

Here v is the linear speed and r is the radius of the circular motion. v is defined as the distance traveled to make one revolution ( $2\pi r$ ) divided into the time takes to make one revolution, that is, the period (T).

$v=\frac{2\pi r}{T}(2)$

Replacing (2) in (1) and replacing the given values:

$a_c=\frac{(\frac{2\pi r}{T})^2}{r}\\a_c=\frac{4\pi^2 r}{T^2}\\a_c=\frac{4\pi^2 (1.85m)}{(2.75s)^2}\\a_c=9.66\frac{m}{s^2}$

7 0

3 years ago

The amount of inertia of an object depends on its __________________________________.

Art [367]

Answer:

first one :

the object will stay at the same speed and direction unless it is acted upon by an internal unbalanced force.

7 0

3 years ago

A clock mechanism at rest has a period of exactly 1 second. When this clock is observed while moving with a speed of 0.80 c, wha

grigory [225]

Answer:

1.67 s

Explanation:

Since the clock is moving at relativistic speed, the period dilates. So, we use the equation

t = t₀/√[1 - (v/c)²].

Given that t = the period of the clock = 1 s and v = speed of the clock = 0.80c, substituting these values into t, we have

t = t₀/√[1 - (v/c)²]

t = 1/√[1 - (0.8c/c)²]

t = 1/√[1 - (0.8)²]

t = 1/√[1 - 0.64]

t = 1/√0.36

t = 1/0.6

t = 1.67 s

So the period of the clock when it is observed while moving with a speed of 0.8c is 1.67 s

6 0

3 years ago

In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur

Marianna [84]

Answer:

According to the instructions given, only options a and b are correct.

That is,

C = (5/3) - (4D/3)

C = 1 – (5D/2)

D= -4/7

C= 17/7

Explanation:

3C + 4D = 5 and 2C + 5D = 2

So, following the instructions from the question,

1) we'll pick the variable with the smallest coefficient and isolate it.

In eqn 1, C has the smallest coefficient,

3C = 5 - 4D (isolated!)

In eqn 2, C still has the smallest coefficient,

2C = 2 - 5D

2) Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient.

For eqn 1,

3C = 5 - 4D, divide through by the coefficient of C,

C = (5/3) - (4D/3)

This matches option a perfectly.

For eqn 2,

2C = 2 - 5D, divide through by the coefficient of C,

C = (2/2) - (5D/2) = 1 - (5D/2)

This matches option b perfectly!

Further solving the equations now,

Since C = C

(5/3) - (4D/3) = 1 - (5D/2)

(5D/2) - (4D/3) = 1 - (5/3)

(15D - 8D)/6 = -2/3

7D/6 = -2/3

D = -4/7

Substituting this into one of the eqns for C

C = 1 - (5D/2)

C = 1 - (5/2)(-4/7) = 1 - (-10/7) = 1 + (10/7) = 17/7.

QED!

8 0

3 years ago

e statements are the same for both nuclear reactions and chemical reactions? Check all that apply. Both can be represented by ba

Lilit [14]

. Both can be represented by balanced equations. Both involve changes to electron arrangements in atoms. Both involve a change in energy. Both result in a change in the identities of elements.

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3 years ago