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3 years ago

What can scientists learn from index fossils?

Chemistry

1 answer:

olga2289 [7]3 years ago

3 0

Answer:

dating and correlating the strata in which it is found

Explanation:

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An oxygen atom has a mass of 2.66 x 10^-23 g and a glass of water has a mass of 0.050kg. Use this information to answer the ques

fomenos

<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>

Explanation:

We know, each mole contains $N_A=$ $6.023 \times 10^{23}$ atoms.

It is given that mass of one oxygen atom is m= $2.66\times 10^{-23}\ g$ .

Therefore, mass of one mole of oxygen, $M=m\times N_A$ .

Putting value of n and $N_A$ ,

$M=2.66\times 10^{-23}\times 6.023\times 10^{23} \ gm\\M=16.0\ gm$

Given,

Mass of water in glass=0.050 kg = 50 gm.

From above part mass of one mole of oxygen atoms = 16.0 gm.

Therefore, number of mole of oxygen equivalent to 50 gm oxygen $=\dfrac{50}{16}=3.1 \ moles.$

LEARN MORE :

Avogadro's number

brainly.com/question/12902286

3 0

3 years ago

What type of radiation is likely to occur when the ratio of protons to neutrons is below the band of stability? a. alpha decay b

Natali [406]

Beta radiation / decay would likely occur when the ratio of protons to neutrons is below the band of stability.

7 0

3 years ago

What bonds are broken and octane combustion?

dedylja [7]

Answer:

Common combustion reactions break the bonds of hydrocarbon molecules,

Explanation:

the resulting water and carbon dioxide bonds always release more energy than was used to break the original hydrocarbon bonds. That's why burning materials mainly made up of hydrocarbons produces energy and is exothermic.

7 0

2 years ago

Using the Bohr model, determine the energy, in joules, necessary to ionize a ground-state hydrogen atom. Show your calculations.

lord [1]

Answer:

The energy required to ionize the ground-state hydrogen atom is 2.18 x 10^-18 J or 13.6 eV.

Explanation:

To find the energy required to ionize ground-state hydrogen atom first we calculate the wavelength of photon required for this operation.

It is given by Bohr's Theory as:

1/λ = Rh (1/n1² - 1/n2²)

where,

λ = wavelength of photon

n1 = initial state = 1 (ground-state of hydrogen)

n2 = final state = ∞ (since, electron goes far away from atom after ionization)

Rh = Rhydberg's Constant = 1.097 x 10^7 /m

Therefore,

1/λ = (1.097 x 10^7 /m)(1/1² - 1/∞²)

λ = 9.115 x 10^-8 m = 91.15 nm

Now, for energy (E) we know that:

E = hc/λ

where,

h = Plank's Constant = 6.625 x 10^-34 J.s

c = speed of light = 3 x 10^8 m/s

Therefore,

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s)/(9.115 x 10^-8 m)

E = (2.18 x 10^-18 J)(1 eV/1.6 x 10^-19 J)

5 0

4 years ago

What is the PH of a 7.5x10^-3 M OH solution

Triss [41]

pH: 11.8750612634
pOH: 2.12493873661
[H+]: 1.33333333333E-12
[OH-]: 0.0075
BASE

5 0

3 years ago

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