Answer:
254.5 K
Explanation:
Data Given
initial volume V1 of neon gas = 12.5 L
final Volume V2 of neon gas = 10.5 L
initial Temperature T1 of neon gas = 30 °C
convert Temperature to Kelvin
T1 = °C +273
T1 = 30°C + 273 = 303 K
final Temperature T2 of neon gas = ?
Solution:
This problem will be solved by using Charles' law equation at constant pressure.
The formula used
V1 / T1 = V2 / T2
As we have to find out Temperature, so rearrange the above equation
T2 = V2 x T1 / V1
Put value from the data given
T2 = 10.5 L x 303 K / 12.5 L
T2 = 254.5K
So the final Temperature of neon gas = 254.5 K
As you can see, the unit of heat of vaporization is in kJ/mol, while the unit for entropy of vaporization is in J/mol·K. Since it is vaporization, this occurs at the boiling point. Thus, the formula would be:
Boiling Point = ΔHvap/ΔSvap
Make sure the units are consistent.
Boiling point = 55.5 kJ/mol * 1000 J/kJ / 148 J/mol·K = <em>375 K or 102°C</em>
Phosphate group , pentose sugar , nitrogen base nucleotide
Electrons are found in the cloud that's surrounded the nucleus of an atom
Answer:
A)A compound that donates protons
Explanation:
for B it is the defination of bases
