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tatiyna
3 years ago
14

a ship leave port p and sails on a bearing N50 degree E to Port Q 15km away.then it sails on a bearing of S45 degree E to Port R

,20km away​
Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

Port r is 100° from Port p and 26km from Port p

Step-by-step explanation:

Lets note the dimension.

From p to q = 15 km = a

From q to r = 20 km= b

Angle at q = 50° + 45°

Angle at q = 95°

Ley the unknown distance be x

Distance from p to r is the unknown.

The formula to be applied is

X²= a²+ b² - 2abcosx

X²= 15² + 20² - 2(15)(20)cos95

X²= 225+400-(-52.29)

X²= 677.29

X= 26.02

X is approximately 26 km

To know it's direction from p

20/sin p = 26/sin 95

Sin p= 20/26 * sin 95

Sin p = 0.7663

P= 50°

So port r is (50+50)° from Port p

And 26 km far from p

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Harry took a loan from the bank.
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Answer:

The size of Harry's loan is $9000.

Step-by-step explanation:

D(t) models Harry's remaining debt, in dollars, as a function of time t, in months  that is given by :

D(t) =-200t+ 9000

We can see 200 is in negative that means it is getting deducted from the function. So, Harry must be paying this each month against his loan.

Lets put t = 0, that shows no payments have been made.

This will get the amount of loan, before any payments.

D(t)=-200(0)+9000

So,D(t) =9000

Hence, the size of Harry's loan is $9000.

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3 years ago
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Have you tried asking a teacher for help before this


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Answer:

A. 15

Step-by-step explanation:

Width (w): 5

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3 years ago
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Answer:

\approx 11.2\:\mathrm{in}

Step-by-step explanation:

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