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vlabodo [156]
3 years ago
10

Find the missing hypotenuse?

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

the missing hypotenuse is 9.4

Zielflug [23.3K]3 years ago
4 0

the missing hypotenuse is 9.4

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Masja [62]

Answer:

h(2) = 7/4

h(-3) = -2

h(-2) = 11/(-8)

h(-3) - h(-2) = -(5/8)

Step-by-step explanation:

h(x) = (2x^2-x+1) / (3x-2)

h(2) = (2*2^2 - 2 + 1) / (3*2 - 2)

       = (8 - 2 + 1) / (6 - 2)

       = 7/4

h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}

        = (18 + 3 + 1) / (-9 - 2)

        = 22/(-11)

        = -2

h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}

        = (8 + 2 + 1) / (-6 - 2)

        = 11/(-8)

h(-3) - h(-2) = (-2) - {11/(-8)}

                  = -(5/8)

Hope this will help. Please give me brainliest.

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3 years ago
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Answer:

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Step-by-step explanation:

Let L be the larger number and s be the smaller one.

Then we have two equations.

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        6s = L         Substitute the value for L in Equation(1)

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         s = 5

The value of the smaller number is 5.

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