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user100 [1]
3 years ago
6

Find the sum of the sequence 36 37 38 39 ... 109=

Mathematics
1 answer:
uysha [10]3 years ago
8 0
It's an arithmetic sequence:

a_1=36;\ a_2=37;\ a_3=38;\ ...\ ;\ a_{74}=109\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\a_1=36;\ n=74;\ a_{74}=109\\\\S_{74}=\dfrac{36+109}{2}\cdot74=\dfrac{145}{2}\cdot74=72.5\cdot74=5365
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5u + 2 + 4<br> need helpp
Hatshy [7]

Answer:

5u + 6

Step-by-step explanation:

because 5u does not have any like terms, it stays on its own. the 2 and 4 can be added together because they are the same as eachother, leaving you with 5u + 6:)

hope this helps!

5 0
2 years ago
7. A shopkeeper buys 300 identical articles a tota
sashaice [31]

Step-by-step explanation and answers:

300 articles at a total cost of $1500:

        $1500 / 300 = $5 / article

Sells 260 articles at a price 20% above this ^ price:

         20% of $5 is $1,   so $5 + $1 = $6

               Then he sells 260 articles at the price of ^ $6

               260 * $6 = $1560

Each of the remaining articles is sold at a price that's 50% of the 260 he sold.

         He sold those for $6,  so he would now sell the last 40 for $3

               From the remaining 40 articles, he makes 40 * $3, or $120

The shopkeeper made $1560 + $120 = $1680,  which is $180 more than he bought them for ($1500)

Therefore, he made a profit percentage of $180 / $1500,  (the amount of profit over the amount spent).

He made a profit percentage, compared to the cost price, of 12%.

3 0
3 years ago
What is the solution to the compound inequality? –6 ≤ 2x + 6 ≤ 6
maw [93]

∈  ≤ ≥

-6 ≤ 2x + 6 ≤ 6 ( seperate the two inequalities)

2x + 6 ≥ - 6

2x + 6 ≤ 6 (solve the inequalities)

x ≥ -6

x ≤ 0 (find the intersection)

solution is : x ∈  { -6, 0 }

7 0
3 years ago
La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:
77julia77 [94]

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)

y+1=\dfrac{-5+1}{-1}(x-2)

y+1=\dfrac{-4}{-1}(x-2)

y+1=4(x-2)

Using distributive property, we get

y+1=4(x)+4(-2)

y+1=4x-8

Subtract 1 from both sides.

y+1-1=4x-8-1

y=4x-9

Therefore, the correct option is B.

5 0
3 years ago
Need help idk how to slove this
Gemiola [76]

Hi!

I'm not sure how to slove this, but I do know how to solve it ;D

<h3>We can't know the exact value of y, but we can isolate y on one side. First, multiply by z on both sides. </h3>

\frac{x+y}{z*z}=3*z

x + y = 3 * z

<h3>Now subtract x from both sides.</h3>

x - x + y = 3 * z - x

<u>y = 3 * z - x</u>

<h2>The answer is y = 3 * z - x</h2>

Hope this helps! :)

-Peredhel

8 0
3 years ago
Read 2 more answers
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