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3 years ago

Someone help pleasee

Mathematics

2 answers:

andriy [413]3 years ago

7 0

7.2 is the answer bae

Art [367]3 years ago

5 0

Answer:

Step-by-step explanation

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If A is the center of the circle, which of these are radii?

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D. A E

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BEACAUSE THE A IS NEAR TO THE E

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2 years ago

Find the GCF of -10c2d and 15 ca2

jonny [76]

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Step-by-step explanation:

5c is the only value you can take out of both factors

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3 years ago

Which of the following best describes the

ehidna [41]

$k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}$

$Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel$

$Answer:\boxed{C-The\ lines\ intersect\ but\ are\ not\ perpendicular.}$

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3 years ago

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The National Weather Service keeps track of the temperature for a given day in a given city. It also keeps track of this informa

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3 years ago

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Find an equation perpendicular to x=1 and passing through (8,-9)

valina [46]

Answer:

$y=-9$

Step-by-step explanation:

We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).

Note that x=1 is a vertical line since x is 1 no matter what y is.

This means that if our new line is perpendicular to the old, then it must be a horizontal line.

So, since we have a horizontal line, then our equation must be our y-value of our point.

Our y-coordinate of our point (8,-9) is -9.

Therefore, our equation is:

$y=-9$

And this is in standard form.

And we're done!

3 0

3 years ago