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3 years ago

What factors determine whether a species can be present in a place?

Physics

1 answer:

Goshia [24]3 years ago

4 0

The other life there, weather and temperature, Availability of resources like food and water, etc.

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a 2.80 kg mass is dropped from a height of 4.50 m. find its potential energy(PE) when it is 3.00 m above the ground.PLEASE HELP

Dennis_Churaev [7]

Answer:

82.3 J

Explanation:

PE = mgh

PE = (2.80 kg) (9.8 m/s²) (3.00 m)

PE = 82.3 J

5 0

4 years ago

What do you mean by 100W power ?

Alex73 [517]

Answer:

What u mean

Explanation:

Explain to me I guess

8 0

2 years ago

Read 2 more answers

Cloud [144]

Answer:

(B) Sending Messages

Explanation:

A similarity between radio waves and microwaves is that both are used for sending messages and communication

Radio Waves and Microwaves have longer wavelengths and lower frequencies. Longer wavelengths than an x-ray which is in the electromagnetic spectrum and lower frequencies than gamma rays, which are also in the electromagnetic spectrum. They are also both electromagnetic radiation.

5 0

4 years ago

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shows a conical pendulum, in which the bob (the small object at the lower end of the cord) moves in a horizontal circle at const

Contact [7]

Answer:

a) $T=0.40 N$

b) $T=1.9 s$

Explanation:

Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.

The perimeter of a circunference is:

$P=2\pi r=0.94$

$r=\frac{0.94}{2\pi}=0.15 m$

Now, we need to find the angle of the pendulum from vertical.

$tan(\alpha)=\frac{r}{L}=\frac{0.15}{0.90}=0.17$

$\alpha=9.44 ^{\circ}$

Let's apply Newton's second law to find the tension.

$\sum F=ma_{c}=m\omega^{2}r$

We use centripetal acceleration here, because we have a circular motion.

The vertical equation of motion will be:

$Tcos(\alpha)=mg$ (1)

The horizontal equation of motion will be:

$Tsin(\alpha)=m\omega^{2}r$ (2)

a) We can find T usinf the equation (1):

$T=\frac {mg}{cos(\alpha)}=\frac{0.04*9.81}{cos(9.44)}=0.40 N$

We can find the angular velocity (ω) from the equation (2):

$\omega=\sqrt{\frac{Tsin(\alpha)}{mr}}=3.31 rad/s$

b) We know that the period is T=2π/ω, therefore:

$T=\frac{2\pi}{\omega}=\frac{2\pi}{3.31}=1.9 s$

I hope it helps you!

8 0

3 years ago

The formula d = 1.1 t 2 + t + 1 expresses a car's distance (in feet to the north of an intersection, d , in terms of the number

Phantasy [73]

d(t) = 1.1t² + t + 1

The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:

v = Δx/Δt

v = average speed, Δx = change in distance, Δt = elapsed time

Given values:

Δx = d(5) - d(3) = 19.6ft

Δt = 5s - 3s = 2s

Plug in and solve for v:

v = 19.6/2

v = 9.8ft/s

5 0

4 years ago

Read 2 more answers