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3 years ago

If different groups of scientist have access to the same data, how can they draw different conclusions?

Physics

1 answer:

Mkey [24]3 years ago

3 0

I suppose they can interpret the data differently.

I hope this helps!

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Malik formed a hypothesis that an increase in atmospheric oxygen levels by 10% would cause red-legged grasshoppers to grow large

worty [1.4K]

<h2>Answer:</h2>

The option C is the correct answer.

Which is, "He varies the nitrogen and carbon dioxide levels in the air from one trial to the next".

<h3>Explanation:</h3>

The hypothesis of Malik was about the effect of increased oxygen level on the growth of the red-legged grasshoppers.

So the areas of his experiment should be the:

Grasshopper type.
High oxygen level.
Rate of growth of grasshopper.

So all the given options are relevant to his experiment except the third one.

So varying the nitrogen and carbon dioxide level in air could not contribute in his experiment.

<h2 />

8 0

2 years ago

Read 2 more answers

A ball is thrown vertically upward with a speed of 12.0 m/s. (<br> a. How high does it rise?

sdas [7]

It rises till all of its Kinetic energy is converted into potential energy.

so, mgh=(1/2)m(v^2)

so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m

5 0

3 years ago

What is the chemical equation, for li2+h20-li0h, use the drop down menu?

ASHA 777 [7]

The fact I can get is22

6 0

2 years ago

Emeka carried out a reaction in which a gas was given off. He followed the progress of the reaction by measuring the mass of the

pickupchik [31]

Answer:

17.5

1.1 g/min

I know it's one of these, try getting a second opinion

6 0

2 years ago

At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?

kompoz [17]

Answer:

$\lambda=4.81\times 10^{-8}\ m$

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

$\lambda T=2.89\times 10^{-3}$

Here,

$\lambda$ = wavelength

$\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m$

So, the wavelength of the star is $4.81\times 10^{-8}\ m$ .

7 0

2 years ago