<span>When t=0, v=0, d=0
When t=tf, v=41m/s, d=3.5m
We have 2 formulas – the ones corresponding to uniformly accelerated linear movement:
vf=a*t+vo
d=(1/2)*a*t^2+vo*t
Let’s put the data in the formulas:
41m/s=a*t+0=a*t
3.5m=(1/2)*a*t^2+0*t=1/2*a*t^2
You can use a variety of methods to find t and a. I will choose substitution.
t=(41m/s)/a
3.5m=(1/2)*a*((41m/s)/a)^2=(1/2)*a*(41m/s)^2/a^2=(1/2)*(41m/s)^2/a
a=(1/2)*(41m/s)^2/(3.5m)=(1/2)*41^2(m^2/s^2)/(3.5m) a=41^2(m/s^2)/( 2*3.5)=240m/s^2</span>
In the context of electricity the equation for power would be as follows:
V*I=W
The V stands for voltage. The I stands for current. The W stands for power.
The reason why power is symbolized by "W" is because it was named after James Watts.
Answer:
A) False
B) False
C) True
D) True
E) True
Explanation:
A) The formula for tangential speed v in term of angular speed ω and radius of rotation r is

So if the angular speed is constant and 0, the tangential speed is also 0. A) is false
B) False because of the centripetal acceleration:

C) True because of the formula for tangential acceleration in term of angular acceleration α is

D) True because same as D), if it has angular acceleration, it would have a tangential acceleration. Also from B) the centripetal acceleration will come with time as soon as angular speed is generated by angular acceleration.
E) True and same explanation as from B)
Just below the chromosphere, is the photosphere.
Hope this helped!
Answer:
D
Explanation:
light moves in a straight line (sorry if I'm wrong)